Answer:
The correct answer is 1,51%
Step-by-step explanation:
To get the probability equally likely of the first 6 examined that have a defective compressor, we use the following formula
P=# of possibilities that meet the condition / #of equally likely possibilities.
As there are multiple events , and all must be achieve, we multiply the probabilities.
P1=7 / 11
P2=6 / 10
P3=5 / 9
P4=4 / 8
P5=3 / 7
P6=2 / 6
P(x)=7 / 11*6 / 10*5 / 9*4 / 8*3 / 7*2 / 6=0,01515151515
P(x)=1,51%
20 x=5 I hope this helps
22.x=15
(9+8+2)/(4+9+8+2)=19/23=82%
Therefore very likely
Answer:
C
Step-by-step explanation:
ok so, assuming that b cannot equal 0, we can divide it on both sides
(3a - 5)/c = b/b
anything divided by itself is 1
(3a - 5)/c = 1
multiply c:
3a - 5 = c
3a = c + 5
a = (c + 5)/3
