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trapecia [35]
3 years ago
5

Can someone please help me with this problem???

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

x + 4 = 5x - 6

x = 2.5

Step-by-step explanation:

x + 4 = 5x - 6

4 = 4x -6

10 = 4x

x = 2.5

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Rewrite y =<img src="https://tex.z-dn.net/?f=%5Csqrt9%7Bx%7D%20%2B45" id="TexFormula1" title="\sqrt9{x} +45" alt="\sqrt9{x} +45"
tigry1 [53]

Answer:

(1) We have been given a function: y=\sqrt{9x}+45-2

We can rewrite it using translation is:  

It is the graph of y=\sqrt{9x} translated 45 units left and 2 units down.

(2) Now, y=\sqrt{x}-5-2

So this is the graph of y=\sqrt{x} translated 5 units right and 2 units down.

(3) y=\sqrt{x}+5-2

So, this is the graph of y=\sqrt{x} translated 5 units left and 2 units down.

(4) y=\sqrt[3]{x}+5-2

It is the graph of y=\sqrt[3]{x}

translated 5 units left and 2 units down.

(5) y=\sqrt[3]{x}+5-2

It is the graph of y=\sqrt[3]{x}

translated 5 units left and 2 units down.

8 0
3 years ago
Hey can anybody help me with this question please
PIT_PIT [208]
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3 years ago
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seraphim [82]
Sorry not in high school
7 0
3 years ago
Describe each step taken to solve the equation. Then, check the solution to see if it is valid. If it is not a valid solution, e
TEA [102]

Answer:

Step-by-step explanation:

given,

a) √x + 6 = 4                                                    

to solve the above equation subtract both side with 6

    √x + 6 - 6  = 4 - 6                  

                √x  = -2                  

squaring both side

                (√x)² = (-2)²              

                       x = 4            

a) ∛x + 6 = 4                                            

to solve the above equation subtract both side with 6

    ∛x + 6 - 6  = 4 - 6

                ∛x  = -2

cubing  both side

                (√x)³ = (-2)³

                      x = -8

4 0
3 years ago
Find the equation of a line containing the given point and slope (10,5); m=9/20
ohaa [14]
\bf \begin{array}{lllll}&#10;&x_1&y_1\\&#10;%   (a,b)&#10;&({{ 10}}\quad ,&{{ 5}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{9}{20}&#10;\\\\\\&#10;% point-slope intercept&#10;y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-5=\cfrac{9}{20}(x-10)\\&#10;\left. \qquad   \right. \uparrow\\&#10;\textit{point-slope form}&#10;\\\\\\&#10;y-5=\cfrac{9}{20}x-\cfrac{9}{2}\implies y=\cfrac{9}{20}x-\cfrac{9}{2}+5\implies y=\cfrac{9}{2}x+\cfrac{1}{2}
6 0
3 years ago
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