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trapecia [35]
3 years ago
5

Can someone please help me with this problem???

Mathematics
1 answer:
hammer [34]3 years ago
8 0

Answer:

x + 4 = 5x - 6

x = 2.5

Step-by-step explanation:

x + 4 = 5x - 6

4 = 4x -6

10 = 4x

x = 2.5

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10. A In the adjoining Figure, ab is perpendicular to bc and ed is to cd while bc=cd . prove i) triangle abc is corresponding to
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<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>

1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)

2) Angles ABC and CDE are right angles (perpendicular lines form right angles)

3) Angles ABC and CDE are equal (all right angles are equal)

4) Angles ACB and DCE are equal (vertical angles are equal)

5) Triangles ABC and EDC are congruent (ASA)

<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>

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4 0
2 years ago
In the triangle below, find the measurements of the unknown angles.
LUCKY_DIMON [66]

Answer:

E. 35°, 70°

Step-by-step explanation:

Sum of angles add up to 180° in every triangle.

Step 1: Set up equation

a + 2a + 75 = 180

Step 2: Combine like terms

3a + 75 = 180

Step 3: Subtract 75 on both sides

3a = 105

Step 4: Divide both sides by 3

a = 35

So 1 angle is 35°

Step 5: Plug in <em>a</em> to find last angle

2(35) = 70°

7 0
3 years ago
What is the following product? Sqr5x^8y^2 sqr10x^3 sqr12y
PSYCHO15rus [73]

Step-by-step explanation:

\sqrt{5 {x}^{8} {y}^{2}  }  \times  \sqrt{10 {x}^{3} } \times  \sqrt{12y}   \\  \\  =   {x}^{4} y \sqrt{5}  \times x \sqrt{10x}  \times 2 \sqrt{3y}  \\  \\  = 2 {x}^{5} y \sqrt{5 \times 10x \times 3y}  \\  \\  =  2 {x}^{5} y \sqrt{5 \times 5 \times 2x \times 3y}  \\  \\ =  2 {x}^{5} y  \times 5\sqrt{ 2x \times 3y}   \\  \\  = 10 {x}^{5} y \sqrt{6xy}  \\

4 0
3 years ago
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Ber [7]

Yes she can find the average colour by adding up all the amount of colors by how many colors there are.

6 0
3 years ago
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For a track meet, Tara ran the 1,600 m event at constant speed in 5 minutes and 20 seconds. What was her speed?
9966 [12]

Answer:

300 m/min

Step-by-step explanation:

Using the general formula of d = rt, where d = distance, r = rate and t = time, we can solve for the missing variable (r, or speed). Given Tara's distance of 1600 m and her total time of 5 minutes and 20 seconds, first convert her time into just minutes:

5 \frac{20}{60}=\frac{1}{3}

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Solve for 'r': 300 meters per minute

4 0
3 years ago
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