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il63 [147K]
3 years ago
14

The average of −8 and 7 according to my online hw thingy 1/2 is incorrecto

Mathematics
1 answer:
kirill [66]3 years ago
7 0
Add -8 + 7. You get -1.
-1 ÷ 2 is -.5, or -1/2. 
You forgot the negative.
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The length of a table is 8 times longer then it’s width. If the perimeter is 72, how wide is the table?
Andrews [41]

Answer:

4 units wide

Step-by-step explanation:

Let the width of the table be 'w'

Given:

Perimeter of the table is, P=72

The perimeter of the rectangular table is given as the sum of all the sides of the rectangle. The sides include two lengths and two widths.

Length of the table is 8 times longer than its width. Therefore,

Length,L=8w

Now, perimeter is given as:

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Now, plug in 72 for 'P' and solve for 'w'. This gives,

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6 0
3 years ago
HELPP!!!!!!!!!!!!!!!!
Anvisha [2.4K]

Answer:

Step-by-step explanation:

We'll take this step by step.  The equation is

8-3\sqrt[5]{x^3}=-7

Looks like a hard mess to solve but it's actually quite simple, just do one thing at a time.  First thing is to subtract 8 from both sides:

-3\sqrt[5]{x^3}=-15

The goal is to isolate the term with the x in it, so that means that the -3 has to go.  Divide it away on both sides:

\sqrt[5]{x^3}=5

Let's rewrite that radical into exponential form:

x^{\frac{3}{5}}=5

If we are going to solve for x, we need to multiply both sides by the reciprocal of the power:

(x^{\frac{3}{5}})^{\frac{5}{3}}=5^{\frac{5}{3}}

On the left, multiplying the rational exponent by its reciprocal gets rid of the power completely.  On the right, let's rewrite that back in radical form to solve it easier:

x=\sqrt[3]{5^5}

Let's group that radicad into groups of 3's now to make the simplifying easier:

x=\sqrt[3]{5^3*5^2} because the cubed root of 5 cubed is just 5, so we can pull it out, leaving us with:

x=5\sqrt[3]{5^2} which is the same as:

x=5\sqrt[3]{25}

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Step-by-step explanation:

This shouldn't be in mathematics?

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