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3 years ago

Factor x^3-4x^2-3x+18=0 given that 3 is a zero.

Mathematics

1 answer:

Mandarinka [93]3 years ago

3 0

Answer:

B: (x + 2)(x - 3)^2

Step-by-step explanation:

This is only going to have 3 roots. One of them is (x - 3)

D does not look right. So let's solve it using synthetic division.

3 || 1 - 4 -3 18

3 -3 -18

========================

1 -1 -6 0

So what you have is a quadratic

x^2 - x - 6 = 0 which will factor
(x - 3)(x + 2) = 0
x - 3 = 0
x = 3
x + 2 =0
x = - 2
(x - 3)(x - 3)(x + 2 ) = 0

The answer is B

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If the gradient of the tangent to

Marizza181 [45]

Answer:

Point A(9, 3)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Coordinates (x, y)
Functions
Function Notation
Terms/Coefficients
Anything to the 0th power is 1
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$
Exponential Rule [Root Rewrite]: $\displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle y = \sqrt{x}$

$\displaystyle y' = \frac{1}{6}$

Step 2: Differentiate

[Function] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y = x^{\frac{1}{2}}$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}}$
[Derivative] Rewrite [Exponential Rule - Rewrite]: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}}$
[Derivative] Rewrite [Exponential Rule - Root Rewrite]: $\displaystyle y' = \frac{1}{2\sqrt{x}}$

Step 3: Solve

Find coordinates of A.

x-coordinate

Substitute in y' [Derivative]: $\displaystyle \frac{1}{6} = \frac{1}{2\sqrt{x}}$
[Multiplication Property of Equality] Multiply 2 on both sides: $\displaystyle \frac{1}{3} = \frac{1}{\sqrt{x}}$
[Multiplication Property of Equality] Cross-multiply: $\displaystyle \sqrt{x} = 3$
[Equality Property] Square both sides: $\displaystyle x = 9$

y-coordinate

Substitute in x [Function]: $\displaystyle y = \sqrt{9}$
[√Radical] Evaluate: $\displaystyle y = 3$

∴ Coordinates of A is (9, 3).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

7 0

3 years ago

How do I workout/find the unknown angles please

Cerrena [4.2K]

Answer: x = 135 degrees and y = 225 degrees.

Step-by-step explanation: To solve this problem we first use the equation (n-2)*180 [n being the number of sides] to find the sum of interior angles in the figure. We plug the values in: (8-2)*180 = 6*180 degrees = 1080 degrees. We divide this by 8 to get the measure of an interior angle: 1080 degrees/8 = 135 degrees. Since all the interior angles of a regular polygon are congruent, we can say that angle x + angle y = 360 degrees. Thus subtract x degrees from 360 degrees to get y: 360 degrees - 135 degrees = 225 degrees. Therefore, x = 135 degrees and y = 225 degrees.

6 0

2 years ago

The functions f(x)=−3/4x+2 1/4 and g(x)=(1/2)^x+1 are shown in the graph.

Svet_ta [14]

-3x/4 + 9/4 = (1/2)^x + 1
-3x/4 - 2^-x = -5/4

(Using log rules)

㏑|-3x/4| - ㏑|2^-x| = ㏑|-5/4|
㏑|3x/4| - x㏑|2| = ㏑|5/4|
e^㏑|3x/4| - e^㏑|2|x = e^㏑|5/4|
|3x/4| - 2x = 5/4
|3x| - 8x = 5
|3x-8x| = 5
|-5x| = 5
|5x| = 5
x=1, -1

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3 years ago

In a circle, what does the ratio A/r^2 represent?

Pepsi [2]

The ratio A/r² would represent $\pi$ which is the circumference of a circle divided by its diameter.

You can see this because the area of a circle is $\pi$ r² and if you divided that by the radius squared, you are given pi which is the circumference of a circle divided by its diameter.

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3 years ago

What are scale drawings? can you give an example?

Alecsey [184]

Scale Drawings are drawings that are used to show the true size of something.
Scale drawings are most commonly used in maps, or in large scale drawings. These show the scale of something. It may show that 1cm is equivalent to 1km, which would allow someone to measure the map to see how far the distance it. It also allows a map to be made smaller, and less detailed- making it often easier to read.
Hope this helps :)

7 0

3 years ago