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Fynjy0 [20]
3 years ago
7

Approximate area under the curve f(x) =-x^2+2x+4 from x=0 to x=3 by using summation notation with six rectangles and use the the

right endpoint value for x to calculate the height​
Mathematics
1 answer:
bekas [8.4K]3 years ago
6 0

Answer:

Summation notation:

\frac{1}{2}\sum_{k=1}^6f((.5k))

or after using your function part:

\frac{1}{2}\sum_{k=1}^6(-(.5k)^2+2(.5k)+4)

After evaluating you get 11.125 square units.

Step-by-step explanation:

The width of each rectangle is the same so we want to take the distance from x=0 to x=3 and divide by 6 since we want 6 equal base lengths for our rectangles.

The distance between x=0 and x=3 is (3-0)=3.

We want to divide that length of 3 units by 6 which gives a length of a half per each base length.

We are doing right endpoint value so I'm going to stat at x=3. The first rectangle will be drawn to the height of f(3).

The next right endpoint is x=3-1/2=5/2=2.5, and the second rectangle will have a height of f(2.5).

The next will be at x=2.5-.5=2, and the third rectangle will have  a height of f(2).

The fourth rectangle will have a height of f(2-.5)=f(1.5).

The fifth one will have a height of f(1.5-.5)=f(1).

The last one because it is the sixth one will have a height of f(1-.5)=f(.5).

So to find the area of a rectangle you do base*time.

So we just need to evaluate:

\frac{1}{2}f(3)+\frac{1}{2}f(2.5)+\frac{1}{2}f(2)+\frac{1}{2}f(1.5)+\frac{1}{2}f(1)+\frac{1}{2}f(.5)

or by factoring out the 1/2 part:

\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))

To find f(3) replace x in -x^2+2x+4 with 3:

-3^2+2(3)+4

-9+6+4

1

To find f(2.5) replace x in -x^2+2x+4 with 2.5:

-2.5^2+2(2.5)+4

-6.25+5+4

2.75

To find f(2) replace x in -x^2+2x+4 with 2:

-2^2+2(2)+4

-4+4+4

4

To find (1.5) replace x in -x^2+2x+4 with 1.5:

-1.5^2+2(1.5)+4

-2.25+3+4

4.75

To find f(1) replace x in -x^2+2x+4 with 1:

-1^2+2(1)+4

-1+2+4

5

To find f(.5) replace x in -x^2+2x+4 with .5:

-.5^2+2(.5)+4

-.25+1+4

4.75

Now let's add those heights.  After we obtain this sum we multiply by 1/2 and we have our approximate area:

\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))

\frac{1}{2}(1+2.75+4+4.75+5+4.75)

\frac{1}{2}(22.25)

11.125

Okay now if you wanted the summation notation for:

\frac{1}{2}(f(3)+f(2.5)+f(2)+f(1.5)+f(1)+f(.5))

is it

\frac{1}{2}\sum_{k=1}^{6}(f(.5+.5(k-1)))

or after simplifying a bit:

\frac{1}{2}\sum_{k=1}^6 f((.5+.5k-.5))

\frac{1}{2}\sum_{k=1}^6f((.5k))

If you are wondering how I obtain the .5+.5(k-1):

I realize that 3,2.5,2,1.5,1,.5 is an arithmetic sequence with first term .5 if you the sequence from right to left (instead of left to right) and it is going up by .5 (reading from right to left.)

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There are no numbers because it is changing the subject of the equation.

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d=rt

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Wendy is on a long road trip. So far, she has driven 125 miles in 150 minutes.
Vikentia [17]

Answer:

Step-by-step explanation:

125 miles / 150 minutes = 300 miles / x       Criss multiply

Notice that the numerators both have the same units -- miles. Proportions should always be set up that way.

125 x = 150 * 300                  Combine the right

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x = 45000/125

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corinne is taking a train into the city. The train travels at a rate of 45 miles per hour. which quantity depends on the other?​
lana66690 [7]

<u>Complete Question:</u>

Corinne is taking a train into the city. The train travels at a rate of 45 miles per hour. Which quantity depends on the other?

A. The distance traveled depends on the number of hours traveled.

B. The number of hours traveled depends on the speed of the train.

C. The speed of the train depends on the distance traveled.

D. The speed of the train depends on the number of hours traveled.

<u>Answer:</u>

Corinne is taking a train into the city. The train travels at a rate of 45 miles per hour. The distance traveled depends on the number of hours traveled

<u>Step-by-step explanation:</u>

As we know the velocity can de defined as the rate of change of position of objects in a particular time. The formula is given by,

           \text {velocity}=\frac{\text {distance}}{\text {time}}

Here, in the question, rate of speed of train is given as 45 miles per hour. if we keep the velocity as constant one, then distance is directly proportionate to the travelled time

            \text {distance}=\text {velocity} \times \text {time}

If 'v' is constant,

           \text {distance} \propto \text {time}

By this we can conclude that, the distance travelled by the train depends on the time taken to travel to it. Hence option A would be the correct one.

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