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Arte-miy333 [17]
1 year ago
12

Determine which method works, substitution or elimination? 4x^2+3y^2=42x^2-6y^2=-3

Mathematics
1 answer:
GarryVolchara [31]1 year ago
3 0

Given:

\begin{gathered} 4x^2+3y^2=4 \\  \\ 2x^2-6y^2=-3 \end{gathered}

Find the method .

Sol:

\begin{gathered} 4x^2+3y^2=4..............(1) \\  \\ 2x^2-6y^2=-3.............(2) \end{gathered}

2eq(1) + eq(2) then,

8x^2+6y^2=8

Then apply the elimination method.

\begin{gathered} 8x^2+6y^2=8 \\ 2x^2-6y^2=-3 \\ --------- \\ 10x^2=5 \\  \\ x^2=\frac{5}{10} \\  \\ x=\sqrt{\frac{1}{2}} \end{gathered}

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