Answer:
Step-by-step explanation:
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<u>Distance formula</u>
Let P(x, y) = any point on the locus
Let A = (0, 2)
Let B = (-2, 3)
If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):
Therefore, using the distance formula:
Square both sides:
![\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]](https://tex.z-dn.net/?f=%5Cimplies%20x%5E2%2B%28y-2%29%5E2%3D%5Cdfrac%7B1%7D%7B9%7D%5B%28x%2B2%29%5E2%2B%28y-3%29%5E2%5D)
Multiply both sides by 9:
Answer:
a) -4. -9. -2
-3. -5. -7
-8. -1. -6
b) -3. 4. -1
2 0 -2
1. -4 3
Step-by-step explanation:
a) -4. -9. -2
-3. -5. -7
-8. -1. -6
b) -3. 4. -1
2 0 -2
1. -4 3
Answer:
Step-by-step explanation:
2)f(x) = 2x² +4x - 3
a = 2 ; b = 4 ; c = -3
1) Put x = -1 in the equation
f(x) = 2*(-1)² + 4*(-1) -3 = 2 - 4 -3 = -5
Vertex = (-1,-5)
2) Upward
3) Minimum
4) axis of symmetry = -b/2a = -4/2*2=-4/4= -1
x = -1
5) domain: all real numbers (-∞ ,∞)
Range : y ≥ -5 ; [-5 , ∞)
3) f(x) = 3x² - 6x + 4
Vertex : (1,1)
Opening : upward
Minimum
Axis of symmetry: x = 1
Domain: all real numbers
Range: y ≥ 1 ; [1, ∞)
4)f(x) = -x² - 2x - 3
a) Vertex: f(x) = -(-1)² - 2*(-1) - 3 = -1 + 2 - 3 = -2
Vertex( -1,-2)
b) downward
c) Maximum
d) Axis of symmetry: x = 2/-2 = -1
x = -1
e) Domain: all real numbers
Range: y ≤ -2 ; (-∞ , -2]
5)f(x) = 2(x -2)²
a) Vertex: (2, 0)
b) Opening: upward
c) Minimum
d) x = 2
e)Domain: all real numbers
Range: y ≥ 0 ; [0,∞)
Answer:
m<8 is 30°
Step-by-step explanation:
Here are some images that can help you have a better understanding :
5.1g = 35.7
5.1g/5.1 = 35.7/5.1
g = 35.7/5/1
g = 7
hope this helps
