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3 years ago

Please Help!!!!!!!! Only Circled Questions!!!!!!!!!!! Show all Steps

Mathematics

1 answer:

Fudgin [204]3 years ago

8 0

Hello!

I'll solve the first two questions for you and show you how to do them step by step!

4.

We must use a certain formula to find the volume of a cylinder. The formula is:

V = pi * r^2 * h

We already have that information!

Pi = approximately 3.14

Radius = 7.5 in

Height = 3.6 in

Substitute:

(Make sure ro solve it step by step, rather than do it all at once)

V = 3.14 * 7.5^2 * 3.6

V = 176.625 × 3.6

V = 635.85

Rounded to the nearest cubic unit, the volume of this cylinder is 636 inches cubed.

**Don't forget to write a small 3 above inches to indicate that it is cubed!

5.

Aha! This time they haven't given you the radius, but the diameter.

Since the radius is half of the diameter, we must divide the diameter by 2 to find it.

r = d ÷ 2

r = 28 ÷ 2

r = 14 cm

Like the previous question, we have enough information to solve this! We'll use the same formula to calculate the volume of this cylinder.

V = pi * r^2 * h

Pi = Approximately 3.14

Radius = 14 cm

Height = 5 cm

Substitute:

V = 3.14 * 14^2 * 5

V = 615.44 * 5

V = 3,077.2 cm cubed

Rounded to the nearest cubic unit, the volume of this cylinder would be 3,077 centimetres cubed.

REMINDERS:

Use the SAME formula for all of the other questions regarding volume of a cylinder. The formula fof volume is:

V = pi * r^2 * h

Make sure you write the small 3 above it!

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Explanation:

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In the attachment:

Point A = (0,5,2) (in blue color)

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Can someone help me?

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Answer:

I'm not sure from my answer but I'm going to try

A = { a^2 - 4 = 0 }

A = { a^2 = 0+ 4 }

A = { a^2 = 4}

Take root of both sides

A = {a = 2}

A = {2}

B = { -2, -1, 0, 1, 2}

C = { 1, 2, 3, 4, 5, 6,7}

i) A\B

= {2} \ {-2,-1,0,1,2}

= ⌀ ( "null set" )

ii) (A\B) \C

= ( {2} \ {-2,-1,0,1,2} ) \ C

= ⌀ \ C

= ⌀ \ { 1, 2, 3, 4, 5, 6,7}

= ⌀ ( "null set" )

iii) (A ∪ B) \ C

= ( { 2 } ∪ { -2, -1, 0, 1, 2} ) \ C

= { -2, -1, 0, 1, 2} \C

= { -2, -1, 0, 1, 2} \ { 1, 2, 3, 4, 5, 6,7}

= { -2, -1, 0 }

iv) ( A\B) ∩ ( A\C)

= ( { 2 } \ {-2,-1,0,1,2} ) ∩ ( { 2 } \ { { 1, 2, 3, 4, 5, 6,7} )

= ⌀ ∩ ⌀

= ⌀

v) ( A ∩ B ) \ C

= ( { 2 } ∩ { -2, -1, 0, 1, 2 } ) \ C

= { 2 } \ { 1, 2, 3, 4, 5, 6, 7 }

= ⌀ "null set"

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