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Nikolay [14]
3 years ago
7

Solve.

Mathematics
1 answer:
uranmaximum [27]3 years ago
4 0

Answer:

It could fly 10,8 kilometers.

Step-by-step explanation:

The European swallow fly speed is 12 meters per second.

We have to calculate how many kilometers it could fly in 15 minutes.

This can be calculated using the equivalent factors for each of the units:

- 1 km is equivalent to 1,000 meters.

- 1 minute is equivalent to 60 seconds.

We know that the distance travelled by the fly is the product of the speed and the time, so we have:

D=v\cdot t\\\\\\D=12\,\dfrac{m}{s}\cdot15\, min\\\\\\D=12\,\dfrac{m}{s}\cdot(\dfrac{1\,km}{1,000\,m})\cdot15\, min\cdot (\dfrac{60\,s}{1\,min})\\\\\\D=\dfrac{12\cdot 15\cdot 60}{1,000}\,km=\dfrac{10,800}{1,000}\,km\\\\\\D=10,8 \,km

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Find the measure of unknown angle​
Lemur [1.5K]

Answer:

Step-by-step explanation:

z = 102 degree (opposite angles of a parallelogram are equal)

z + x + 34 = 180 degree 9sum of adjacent angles of a parallelogram is 180 degree)

102 + x + 34 = 180

x = 180 - 136

x = 44 degree

y + 102 + x = 180 degree (sum of interior angles of a triangle is 180 degree)

y + 102 + 44 = 180

y = 180 - 146

y = 34 degree

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If the question is True or False then the answer is True


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Please solve this<br> (Rational numbers 8th grade)
pochemuha

                                        Question # 1

Answer:

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}

Step-by-step explanation:

Given the expression

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}

=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}           ∵  \frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}

=-\frac{2}{5}+\frac{1}{4}                        ∵   \frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=\frac{1}{4}

\mathrm{Least\:Common\:Multiplier\:of\:}5,\:4:\quad 20

=-\frac{8}{20}+\frac{5}{20}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{-8+5}{20}

\mathrm{Add/Subtract\:the\:numbers:}\:-8+5=-3

=\frac{-3}{20}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

=-\frac{3}{20}

Therefore,

\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}

                                               Question # 2

Answer:

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}

Step-by-step explanation:

Given

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}

=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}          ∵    \frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}

=-\frac{6}{35}-\frac{1}{140}         ∵   \frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}

\mathrm{Least\:Common\:Multiplier\:of\:}35,\:140:\quad 140

=-\frac{24}{140}-\frac{1}{140}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

=\frac{-24-1}{140}

\mathrm{Subtract\:the\:numbers:}\:-24-1=-25

=\frac{-25}{140}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}

=-\frac{25}{140}

\mathrm{Cancel\:the\:common\:factor:}\:5

=-\frac{5}{28}

Therefore,

\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}

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the sum of three times one number, x, and five times a second number,y, is 77. if the sum of the two numbers is 19, find the two
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Answer:

x=9, y=10. (9, 10). The two numbers are 9 and 10.

Step-by-step explanation:

3x+5y=77

x+y=19

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3x+5y=77

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2y=20

y=20/2

y=10

x+10=19

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x=9

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Answer:

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Step-by-step explanation:

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