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OleMash [197]
4 years ago
8

What is the solution for 2t<5

Mathematics
1 answer:
aliya0001 [1]4 years ago
7 0
T < 5/2
t is less than 5/2 or 2.5
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HOW DO YOU FIND THE SINE, COSINE, AND TANGENT VALUES GIVEN A POINT ON A CIRCLE? BE ABLE TO PROVIDE AN EXAMPLE.
FromTheMoon [43]
Answer: If the point of the circle P has coordinates: P=(x,y)
sine (Angle) = y/r
cosine (Angle) = x/r
tangent (Angle) = y/xw
where r=sqrt(x^2+y^2) is the radius of the circle

Example:
P=(3,4)=(x,y); x=3 and y=4
Radius of the circle: r
r=sqrt(x^2+y^2)
r=sqrt(3^2+4^2)
r=sqrt(9+16)
r=sqrt(25)
r=5

sin(Angle)=y/r
sin(Angle)=4/5

cosine(Angle)=x/r
cosine(Angle)=3/5

tangent(Angle)=y/x
tangle(Angle)=4/3
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4 years ago
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Which statement describes the domain of the function f (x) = StartFraction 3 x Over 4 x squared minus 4 EndFraction?
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Answer:

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Step-by-step explanation:

i just used desmos, never touches x=1 or x=-1

7 0
3 years ago
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8^3*8^-5*8^y=1/8^2, what is the value of y in the product of powers below?
Aleks04 [339]

For this case we have that by definition of multiplication of powers of the same base, the same base is placed and the exponents are added:

a ^ n * a ^ m = a ^ {n + m}

So, we can rewrite the given expression as:

8 ^ {3-5 + y} = \frac {1} {8 ^ 2}\\8 ^ {- 2 + y} = \frac {1} {8 ^ 2}

So, if y = 0:

8 ^ {- 2} = \frac {1} {8 ^ 2}\\\frac {1} {8 ^ 2} = \frac {1} {8 ^ 2}

Equality is met!

Answer:

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Answer:

$11.28 per cd

Step-by-step explanation:

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Solving systems by Substitution Homework y=x+4 y=x-3​
zvonat [6]
There is no solution for this equation since they have the same slope, x/1. The only difference between these two is that their y intercepts are different meaning that they will be parallel lines that will never intersect among one other. For example, think of it as two separate lines that are have the same slope and never gain more distance/units from one another.


Solve:

To solve, you have to get one of this equations into a Ax+By=C equation form, standard equation. Let’s change y=x+4 into a standard equation.

We have to get x and y together and 4 as C.
So let’s subtract x from both sides;

y=x+4
-x -x
————————
-x+y=4

This is a standard equation.

Now let’s substitute.

take the standard equation and plug in y which is x+4 since there is a equation meaning it’s y=x+4


-x+(x+4)=4


Let’s simplify this mess.


-x+x equals 0. So we are left with 4=4.

Subtract 4 from both sides and we get 0=0



This means there is no solution. Hoped this helped.
8 0
3 years ago
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