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OleMash [197]
3 years ago
8

What is the solution for 2t<5

Mathematics
1 answer:
aliya0001 [1]3 years ago
7 0
T < 5/2
t is less than 5/2 or 2.5
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point a has the coordinates(2,5) point B has the coordinates (6,17) how long is segment ab in simplified radical form
IRISSAK [1]

Answer:

4\sqrt{10}

Step-by-step explanation:

We have been given that point A has the coordinates(2,5) point B has the coordinates (6,17).

To find the length of segment AB we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Upon substituting coordinates of point A and point B in distance formula we will get,

\text{Distance between point A and point B}=\sqrt{(6-2)^2+(17-5)^2}

\text{Distance between point A and point B}=\sqrt{(4)^2+(12)^2}

\text{Distance between point A and point B}=\sqrt{16+144}

\text{Distance between point A and point B}=\sqrt{160}

\text{Distance between point A and point B}=4\sqrt{10}

Therefore, the length of segment AB is 4\sqrt{10}.

3 0
3 years ago
Square root of 50 + square root of 18
skelet666 [1.2K]

if ya asking for simpliicatio

remember that \sqrt{ab}=(\sqrt{a})(\sqrt{b})

and

\sqrt{a^2}=(\sqrt{a})(\sqrt{a})=a

\sqrt{50}+\sqrt{18}=

factor

(\sqrt{2})(\sqrt{5})(\sqrt{5})+(\sqrt{2})(\sqrt{3})(\sqrt{3})=

(\sqrt{2})(5)+(\sqrt{2})(3)=

5\sqrt{2}+3\sqrt{2}=

8\sqrt{2}

5 0
3 years ago
What is the value of e^infinity and e^-infinity
valentinak56 [21]
E^(∞): This is defined as 'e' being raised to a huge value. Hence the result will definitely be a large number which is also infinity (∞), i.e. e^(∞) = ∞. e^(- ∞) = 1/e^(∞) = 1/∞ = 0.
8 0
3 years ago
Will award brainliest if answered within 10 minutes!
Pachacha [2.7K]
The answer would be:
y=-\frac{2}{1}x-4

Hope this helps
6 0
3 years ago
Read 2 more answers
CO
8090 [49]

Answer:

A( multiply both sides by 6)

As seen , the L.C.M is 6 so to do away with the fractional form, we will multiply by 6

5 0
3 years ago
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