Write a variable expression for each word phrase: the product of c and 3

1 answer:

7 0

Variables are symbols that are used to represent a number in an expression or equation.

There's one word phrase here, and it's answer is: c*3

If you need help with another one, just let me know! :)

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JIM TOSSES A BALL IN THE AIR WHEN ON THE COUNT OF 2, 3 , 5 8 13 what numbers will he count when he tosses the ball for the 6th 7

DENIUS [597]

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21, 34, and 55 because it's like that one ratio, I forgot the name tho

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A bag contains 3 red marbles, 4 white marbles, and 5 blue marbles. one marble is randomly selected from the bag. what is the pro

Paha777 [63]

the probability will be 1/3

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List x1, x2, x3, x4 where xi is the right endpoint of the four equal intervals used to estimate the area under the curve of f(x)

anzhelika [568]

From x=a to x=b, with n subintervls, the width between each is (b-a)/n

so from x=3 to x=5 and 4 intervales is (5-3)/4=2/4=1/2

increments of 1/2 each time
we need 4 of them

I see that xi is the right endpoint so I would guess that we take the right <span>Riemann sum
so we start at 3+0.5 or 3.5

so 3.5, 4,4.5,5

C I would say
</span>

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3 years ago

Simplify the expression. Write the answer using scientific notation. Astronomers measure large distances in light-years. One lig

PolarNik [594]

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3 years ago

4x2 + 4x - 1, evaluate and fully simplify each of the - For the function f(0) following f(s + h) f(x + h) - f(5) h 10

Andrew [12]

Given the function f(x);

$f(x)=-4x^2+4x-1$

Evaluating the function f(x+h);

$\begin{gathered} f(x+h)=-4(x+h)^2+4(x+h)-1 \\ f(x+h)=-4(x^2+2xh+h^2)^{}+4(x+h)-1 \\ f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1 \end{gathered}$

So;

$f(x+h)=-4x^2-4h^2-8xh^{}+4x+4h-1$

Evaluating the second function;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1-(-4x^2+4x-1)}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2-4h^2-8xh^{}+4x+4h-1+4x^2-4x+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4x^2+4x^2-4h^2-8xh^{}+4x-4x+4h-1+1}{h} \\ \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h} \end{gathered}$

simplifying further;

$\begin{gathered} \frac{f(x+h)-f(x)}{h}=\frac{-4h^2-8xh^{}+4h}{h}=-4h-8x+4 \\ \frac{f(x+h)-f(x)}{h}=-4h-8x+4 \end{gathered}$

Therefore, we have;

$undefined$

7 0

1 year ago