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rewona [7]
3 years ago
11

Write a variable expression for each word phrase: the product of c and 3

Mathematics
1 answer:
mash [69]3 years ago
7 0
Variables are symbols that are used to represent a number in an expression or equation. 

There's one word phrase here, and it's answer is: c*3

If you need help with another one, just let me know! :)
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1. COLLEGE A local college recently
fomenos

Answer: 18482

Step-by-step explanation:

8% of 17113 is 1369

1369 + 17113 = 18482

4 0
3 years ago
48 girls, 41 boys, and 5 teachers sat in the gym. Write the ratio of girls to boys in three ways.
Anika [276]

Answer:

D

Step-by-step explanation:

The answer is D because the question is asking for girls to boys. So anything that has 5 in it is wrong because it isn't asking for teachers, which eliminates A. So since it is asking <u>girls</u><u> </u><u>to</u><u> </u><u>boys</u> the number order has to be 48 then 41 because it is asking for girls first then to boys. So that makes B wrong. When it comes to the fraction part of the ratio the first number it is asking for (which is girls) <em><u>alwa</u><u>ys</u></em> goes on top. So that eliminates C which leaves only answer to be D.

7 0
3 years ago
I NEED HELP IM LATE PLEASE
Inga [223]

Answer:

9x, 8x+12

Step-by-step explanation:

x(2x+7)-2x(x-1)

=> 9x

3 0
3 years ago
Prove the following
fomenos

Answer:

Step-by-step explanation:

\large\underline{\sf{Solution-}}

<h2 /><h2><u>Consider</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \dfrac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \}cos(23π+x)cos(2π+x)

<h2><u>W</u><u>e</u><u> </u><u>K</u><u>n</u><u>o</u><u>w</u><u>,</u></h2>

\rm \: \cos \bigg( \dfrac{3\pi}{2} + x \bigg) = sinx

\rm \: {cos \: (2\pi + x) }

\rm \: \cot \bigg( \dfrac{3\pi}{2} - x \bigg) \: = \: tanx

\rm \: cot(2\pi + x) \: = \: cotx

So, on substituting all these values, we get

\rm \: = \: sinx \: cosx \: (tanx \: + \: cotx)

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{sinx}{cosx} + \dfrac{cosx}{sinx}

\rm \: = \: sinx \: cosx \: \bigg(\dfrac{ {sin}^{2}x + {cos}^{2}x}{cosx \: sinx}

\rm \: = \: 1=1

<h2>Hence,</h2>

\boxed{\tt{ \cos \bigg( \frac{3\pi}{2} + x \bigg) \cos \: (2\pi + x) \bigg \{ \cot \bigg( \frac{3\pi}{2} - x \bigg) + cot(2\pi + x) \bigg \} = 1}}

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

<h2>ADDITIONAL INFORMATION :-</h2>

Sign of Trigonometric ratios in Quadrants

  • sin (90°-θ)  =  cos θ
  • cos (90°-θ)  =  sin θ
  • tan (90°-θ)  =  cot θ
  • csc (90°-θ)  =  sec θ
  • sec (90°-θ)  =  csc θ
  • cot (90°-θ)  =  tan θ
  • sin (90°+θ)  =  cos θ
  • cos (90°+θ)  =  -sin θ
  • tan (90°+θ)  =  -cot θ
  • csc (90°+θ)  =  sec θ
  • sec (90°+θ)  =  -csc θ
  • cot (90°+θ)  =  -tan θ
  • sin (180°-θ)  =  sin θ
  • cos (180°-θ)  =  -cos θ
  • tan (180°-θ)  =  -tan θ
  • csc (180°-θ)  =  csc θ
  • sec (180°-θ)  =  -sec θ
  • cot (180°-θ)  =  -cot θ
  • sin (180°+θ)  =  -sin θ
  • cos (180°+θ)  =  -cos θ
  • tan (180°+θ)  =  tan θ
  • csc (180°+θ)  =  -csc θ
  • sec (180°+θ)  =  -sec θ
  • cot (180°+θ)  =  cot θ
  • sin (270°-θ)  =  -cos θ
  • cos (270°-θ)  =  -sin θ
  • tan (270°-θ)  =  cot θ
  • csc (270°-θ)  =  -sec θ
  • sec (270°-θ)  =  -csc θ
  • cot (270°-θ)  =  tan θ
  • sin (270°+θ)  =  -cos θ
  • cos (270°+θ)  =  sin θ
  • tan (270°+θ)  =  -cot θ
  • csc (270°+θ)  =  -sec θ
  • sec (270°+θ)  =  cos θ
  • cot (270°+θ)  =  -tan θ
7 0
2 years ago
Read 2 more answers
The Junior Beta club needs to raise $1513.75 to go to a national convention. If they decided to sell candy bars at $1.25 each, h
rusak2 [61]

Answer:

1,211 candy bars.

Step-by-step explanation:

You divide the goal by how much the bars are selling for, or 1513.75/1.25.   The answer to this is 1,211 candy bars.

4 0
3 years ago
Read 2 more answers
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