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jok3333 [9.3K]
3 years ago
14

If you increase your current quality score of 85% by 7%,

Mathematics
2 answers:
svlad2 [7]3 years ago
5 0
85 x 0.07 = 5.95

Total = 85 + 5.95 = 90.95%
Gennadij [26K]3 years ago
3 0

Answer:

90.95%  

Step-by-step explanation:

It has been given that our current quality score is 85%. We are asked to find our new quality score after an increase of of 7%.

\text{New score}=\text{Old score + Increase in old score}

\text{New score}=85+7\%\text{ of }85  

\text{New score}=85+(\frac{7}{100}\times 85)

\text{New score}=85+(0.07\times 85)

\text{New score}=85+5.95

\text{New score}=90.95  

Therefore, the new score will be 90.95%.

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If 1 cm = 0.394 inches, how many inches are in 1 kilometer?
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Naval intelligence reports that 99 enemy vessels in a fleet of 1818 are carrying nuclear weapons. If 99 vessels are randomly tar
oee [108]

Answer:

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

Step-by-step explanation:

The vessels are destroyed and then not replaced, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 18 means that N = 18

9 are carrying nuclear weapons, which means that k = 9

9 are destroyed, which means that n = 9

What is the probability that no more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X \leq 1) = P(X = 0) + P(X = 1)

In which

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,18,9,9) = \frac{C_{9,0}*C_{9,9}}{C_{18,9}} = 0.000021

P(X = 1) = h(1,18,9,9) = \frac{C_{9,1}*C_{9,8}}{C_{18,9}} = 0.001666

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.000021 + 0.001666 = 0.001687

0.001687 = 0.1687% probability that no more than 1 vessel transporting nuclear weapons was destroyed.

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3 years ago
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Fofino [41]
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2. Analytical. Calculate the derivative of the function f(x)
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Replace x=-2 in the f(x) function and you'll get the value of y:
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You get the same answer: x=-2, y=-9

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<span>B. (-2, -9)</span>

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