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3 years ago

Solve for N 2/7 = 10/N

Mathematics

1 answer:

7nadin3 [17]3 years ago

4 0

Answer:

N=35

Step-by-step explanation:

Given equation is represented as:

2/7 = 10/N

Since the equation is expressed in fractional form, let us multiply both left hand side and right hand side by N:

2/7 * N = 10/N * N

=> 2N/7 = 10

Multiplying both left hand side and right hand side by 7:

2N/7*7 =10*7

=> 2N = 70

Dividing both left hand side and right hand side by 2:

2N/2 = 70/2

=> N = 70/2 = 35

Hence the required value of N is 35.

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Describe fully the single transformation which takes shape a to shape b

Leni [432]

Answer:

<h2>Reflection across the y-axis and 1 unit shift downside.</h2>

Step-by-step explanation:

Notice that shape A is in the second quadrant and shape B is in the first quadrant. That means there was a reflection across y-axis and then the figure was shifted one unit downside.

Therefore, the transformation was reflection across the y-axis and 1 unit shift downside. Which is a rigid transformation, because the shape and size didn't change.

4 0

3 years ago

Howard is designing a chair swing ride. The swing ropes are 4 44 meters long, and in full swing they tilt in an angle of 2 3 ∘ 2

qaws [65]

Question:

Howard is designing a chair swing ride. The swing ropes are 4 meters long, and in full swing they tilt in an angle of 23°. Howard wants the chairs to be 3.5 meters above the ground in full swing. How tall should the pole of the swing ride be? Round your final answer to the nearest hundredth.

Answer:

7.18 meters

Step-by-step explanation:

Given:

Length of rope, L = 4 m

Angle = 23°

Height of chair, H= 3.5 m

In this question, we are to asked to find the height of the pole of the swing ride.

Let X represent the height of the pole of the swing ride.

Let's first find the length of pole from the top of the swing ride. Thus, we have:

$cos \theta = \frac{h}{L}$

Substituting figures, we have:

$cos(23) = \frac{h}{4}$

Let's make h subject of the formula.

$h = 4cos(23) = 3.68$

The length of pole from the top of the swing ride is 3.68 meters

To find the height of the pole of the swing ride, we have:

X = h + H

X = 3.68 + 3.5

X = 7.18

Height of the pole of the swing ride is 7.18 meters

3 0

3 years ago

Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv

liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0

3 years ago

Trapezoid ABCD below is to be translated to

Anarel [89]

Answer:

17x+13y

Step-by-step explanation:

6 0

3 years ago

What is the volume of a hemisphere with a diameter of 8 inches?

USPshnik [31]

Answer:

Mind if ya brainiest meh

Step-by-step explanation:

The volume of the hemisphere is 1071.78 ft^3

7 0

3 years ago