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3 years ago

10

Determine the domain and range of the function f(×)=

TexFormula1" title="2 \sqrt[3]{108} 2x" alt="2 \sqrt[3]{108} 2x" align="absmiddle" class="latex-formula">

2 answers:

zhannawk [14.2K]3 years ago

5 0

Answer:

Simplifies to:

748.245949x

Liono4ka [1.6K]3 years ago

4 0

Answer: a) {x| all real numbers}; {y| y>0}

Step-by-step explanation: i just took the test it was right for me

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The sum of three numbers is 69. If the second number is equal to the first diminished by 8, and the third number is 5 times the

julsineya [31]

(5)x=8 ....(5)x mean multiply 5

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4 years ago

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If x has a mean of 17.2 g and a standard division of 14.0 g and y has a mean of 23.5 g and a standard division of 16.4 g and the

dimulka [17.4K]

The least squares regression line is y=0.6831x+11.25

Step-by-step explanation:

LSRL is the the Least Squares Regression Line.The formula for regression line is y=mx+b where m is the slope of the line and b is the y-intercept value of the line.

First find the slope, m of the line from the means and standard deviations given

x has a mean of 17.2 g and a standard deviation of 14.0 g

y has a mean of 23.5 g and a standard deviation of 16.4 g

The correlation coefficient in both cases is 0.83, hence the slope m is given by;

m=r(Sy/Sx) where m is the slope of the line, Sy is standard deviation of y values, Sx is standard deviation of x values and r is the correction coefficient.

m= 0.5 * 23.5/17.2 =0.6831

Find the value of b, the y-intercept

b=Y-mX where X and Y are the mean values for x and y respectively

b=23.5-0.6831*17.2

b=23.5-11.75=11.25

The LSRL is y=0.6831x+11.25

Learn More

Least Squares regression Line : brainly.com/question/4090838

Keyword : standard deviation, least square regression line

#LearnwithBrainly

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3 years ago

Which expression represent the series

Inessa05 [86]

I believe B But I am not sure I hope this helps . =D

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4 years ago

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A ball rolls down an inclined plane such that the distance (in centimeters) that it rolls in t seconds is given by s(t) = 2t^3 +

IRISSAK [1]

The ball's velocity will be represented by the derivative of its distance function:

$s'(t)=6t^2+6t$

Now find the times $t$ for which this is equal to 30, i.e. solve

$6t^2+6t=30\implies t^2+t-5=0$

This has two solutions, $t=-\dfrac{1\pm\sqrt{21}}2$ , but only one is positive and falls in the interval $[0,3]$ . So the velocity reaches 30 cm/s when $t=-\dfrac{1-\sqrt{21}}2\approx1.79$ .

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3 years ago

How many solutions does this equation have?

Bess [88]

Answer: One solution (1 1/6)

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3 years ago

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