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zhannawk [14.2K]
4 years ago
10

I need geometry help!!

Mathematics
1 answer:
Tresset [83]4 years ago
3 0

Answer: i gave you another example i just had to help you

Step-by-step explanation:

A)  8²+ 10²=x²

 

B) x + 8 = 10

 

C)  x²+8²=10

 

D)  x²+ 10²=8²

 

EXPLANATION:

A)  

Incorrect. In this triangle, you know the hypotenuse (the side opposite the right angle) has a length of 10. The lengths of the legs are 8 and x. The correct answer is .

 

B) x + 8 = 10

Incorrect. The Pythagorean Theorem is a relationship between the lengths of the sides squared. The correct answer is .

 

C)  

Correct. In this triangle, the hypotenuse has length 10, and the legs have length 8 and x. Substituting into the Pythagorean Theorem you have: ; this equation is the same as , or . What number, times itself, equals 36? That would make x = 6.

 

D)  

Incorrect. In this triangle, the hypotenuse has length 10 (always the longest side of the triangle and the side opposite the right angle) not 8. The correct answer is

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In one hour Dele walks 8km. How<br> long will it take her to walk 14km at<br> the same rate?
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Answer:

1.45 h

Step-by-step explanation:

common factor of 8 and 14 is 2.

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I have one half of a square and i want to divide it one eighth how many pieces would I have
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You will have 4 pieces.

<u><em>Explanation</em></u>

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4 years ago
If the shaded area is 23cm^2, then what is the smallest possible value of the inner area?
bagirrra123 [75]

Answer:

I suspect it can = 0 when the roots are solved for.

x = 10.44 which is the only positive root. There is another one, but I think it gives a minus number for the white area.

Step-by-step explanation:

There are two areas that are possible given the dimensions of the two rectangles. The trick is to find both of them. and compare.


Step One  

Find the area of the inside rectangle (unshaded area)


Area = (2x - 1)*x Use the distributive property to find the area


Area = 2x^2 - x  


Step Two


Find the area of the outside of the frame


Area = (x + 5)(x + 3) Remove the brackets using FOIL


Area = x^2 + 5x + 3x + 15


Area = x^2 + 8x + 15


Step Three

Find the area of the shaded region


Area shaded = x^2 + 8x + 15 – (2x^2 – x)                  Remove the brackets


Area shaded = x^2 + 8x + 15 – 2x^2 + x                    Combine like terms  


Area shaded = x^2 + 9x + 15 - 2x^2


Area shaded = -x^2 + 9x + 15

Step Four


Find the roots of the quadratic.

a = -1

b = 9

c = 15

Using the quadratic formula, and substituting for a b and c, we get

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a}  

\text{x = }\dfrac{ -9 \pm \sqrt{9^{2} - 4*(-1)(15 } }{2(-1)}  

\text{x = }\dfrac{ -9 \pm \sqrt{81  + 4*(1)(15 } }{2(-1)}

There  is only 1 value that works for this problem and that is when x = 10.44

4 0
4 years ago
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