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3 years ago

What is 60/d when D =10

Mathematics

2 answers:

mina [271]3 years ago

8 0

Plug in d and you get 60/10 and then divide to get 6 as the answer

anygoal [31]3 years ago

6 0

Divide 60 by 10 , you get 6

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Select the graph for the solution of the open sentence. Click until the correct graph appears. |x| > 3/2

Soloha48 [4]

ANSWER

See attachment

EXPLANATION

The given inequality is

$|x| \: > \: \frac{3}{2}$

This implies that,

$x\: > \: \frac{3}{2} \: or \: - x\: > \: \frac{3}{2}$

Multiply both sides of the second inequality by -1 and reverse the inequality sign.

$x\: > \: \frac{3}{2} \: or \: x\: < \: - \frac{3}{2}$

The graphical solution to this inequality is shown in the attachment.

7 0

3 years ago

Una recta que pasa por los puntos A (2,1) y B (6,3) y otra recta pasa por A y por el punto (0,y) ¿Cuánto vale y, si ambas rectas

ASHA 777 [7]

The translation of the question given is

A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?

Answer:

y = 5

Step-by-step explanation:

Line 1 that passes through A (2,1) and B (6,3)

Slope (m1) = 3-1/6-2 = 2/4 = 1/2

y - 1 = $\frac{1}{2}$ ( x -2)

2y - 2 = x- 2

y = $\frac{x}{2}$

Line 2 passes through A (2,1) and (0,y)

slope (m2) = $\frac{y-1}{-2}$

Line 1 and Line 2 are perpendicular

m1*m2 = -1

$\frac{1}{2}$ * $\frac{y-1}{-2}$ = -1

y-1 = 4

y = 5

slope = -2

Equation of Line 2

Y-1 = -2(x-2)

y -1 = -2x +4

2x +y = 5

7 0

2 years ago

I'm not sure how to do this please help

IgorLugansk [536]

Answer:

maria will run 1.75 more miles than her goal

Step-by-step explanation:

If you multiply 2.75 to 7 days you will get 19.25. And if you subtract it by 17.5(because that's her goal) you will get 1.75.

So the answer to this question would be:

Maria will run 1.75 more mile than her goal.

7 0

3 years ago

Please please please help me with this answer

Art [367]

Let blueberry = b and poppyseed = p

b + p = 64

b = p + 20

p + 20 + p = 64

2p + 20 = 64

2p = 44

p = 22

b = 22 + 20

b = 42

Jack bought 42 blueberry muffins

3 0

2 years ago

Solve the following pair of equations simultaneously.

Alchen [17]

Answer:

No solutions.

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS
Equality Properties

Algebra I

Solving systems of equations using substitution/elimination
Solving systems of equations by graphing
Expanding
Finding roots of a quadratic
Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Step-by-step explanation:

Step 1: Define systems

2x - y = 9

4x² + 3y² - 2x + y = 16

Step 2: Rewrite systems

2x - y = 9

Subtract 2x on both sides: -y = 9 - 2x
Divide -1 on both sides: y = 2x - 9

Step 3: Redefine systems

y = 2x - 9

4x² + 3y² - 2x + y = 16

Step 4: Solve for x

Substitution

Substitute in y: 4x² + 3(2x - 9)² - 2x + (2x - 9) = 16
Expand: 4x² + 3(4x² - 36x + 81) - 2x + (2x - 9) = 16
Distribute 3: 4x² + 12x² - 108x + 243 - 2x + 2x - 9 = 16
Combine like terms: 16x² - 108x + 234 = 16
Factor GCF: 2(8x² - 54x + 117) = 16
Divide 2 on both sides: 8x² - 54x + 117 = 8
Subtract 8 on both sides: 8x² - 54x + 109 = 0
Define variables: a = 8, b = -54, c = 109
Resubstitute: $x=\frac{54\pm\sqrt{(-54)^2-4(8)(109)} }{2(8)}$
Exponents: $x=\frac{54\pm\sqrt{2916-4(8)(109)} }{2(8)}$
Multiply: $x=\frac{54\pm\sqrt{2916-3488} }{16}$
Subtract: $x=\frac{54\pm\sqrt{-572} }{16}$

Here we see that we start to delve into imaginary roots. Since on a real number plane, we do not have imaginary roots, there would be no solution to the systems of equations.

Step 5: Graph systems

We can verify our results.

8 0

3 years ago