The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
Must click thanks and mark brainliest
Answer:
The graph in the attached figure
Step-by-step explanation:
we have

Solve for x
Subtract x both sides


Adds 1 both sides


The solution is the interval -------> (3,∞)
All real numbers greater than 3
In a number line is the shaded area at right of x=3 (open circle)
see the attached figure
Hello
<span>2(x-3)+5=4-7(2x-1)
2x-6+5 = 4 -14x+7
2x+14x =6-5+4+7
16x=12
x=12/16
x=(4×3)/(4×4)
x=3/4 (simplified by 4)
answer B</span>
lol, there are three.
Step-by-step explanation:
thanks for the points I guess.