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Ugo [173]
3 years ago
11

What is the slope that crosses through the point (-4,-5) and (6,8)

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0
Slope = \frac{Y2 - Y1}{X2 - X1}

\frac{8 - (-5)}{6 - (-4)}

Your final answer is: \frac{13}{10}
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5 0
2 years ago
Algebra help please?
Alika [10]

Ok, basically if you want to find when both equations are equal just make them equal to each other. 0.925x^2 - 4x + 20  = -1.125x^2 + 6x + 40.

From there use algebraic steps to find out what x is ( the break - even point ).

0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40

0.855625x - 4x + 20 = 1.265625x + 6x + 40

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Tell me if I got something wrong :)

3 0
3 years ago
Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD
Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = \sqrt{75+25} = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that \frac{1}{2} * BF =  \frac{1}{2} * 5 * \sqrt{75} and BF= 0.5\sqrt{75}. Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is  A= BF *  \frac{AB+CD}{2} = 0.5  \sqrt{75}  * \frac{5+10}{2} = 18.75 \sqrt{3}   cm^{2}

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3 years ago
The weight of a box of cereal can vary by 1/4 of an ounce and still be sold as a full box. Each box is supposed to contain 18 ou
Minchanka [31]
It's answer choice B
7 0
3 years ago
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