Answer:
The required linear function is: f(x) = 
Step-by-step explanation:
We are given that f(x) is a linear function and it takes the value 9 when x = 2 and 14 when x = -1.
Now the general form of any linear function is: f(x) = ax + b.
Substituting these values in the general form we get:
f(2) = 9 = 2a + b
f(-1) = 14 = -a + b
Solving these two equations we get:
b = 37/3
Substituting this in the second equation to find 'a'.
a = -5/3
Therefore, the function f(x) =
x +
.
Answer:
1) x= -36.
2) x = 0.
Step-by-step explanation:
1) Taking the 3rd power to both sides and using the following exponent law:

we get:

So this tells us that x = -36.
2) We can distribute the power inside every term. So the left side becomes:

Now, the trick here is to remember that
, so replacing 1 with
, which then gives us:
, telling us that 3x = 0 and thus, x = 0.
Answer:
10(3.14) = 31.4
20(3.14)=62.8
It will be twice the size
<span>Equation at the end of step 1 :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0
</span><span>Step 2 :</span><span>Step 3 :</span>Pulling out like terms :
<span> 3.1 </span> Pull out like factors :
<span> -3x3y7 + x3y - 6y</span> = <span> -y • (3x3y6 - x3 + 6)</span>
Trying to factor a multi variable polynomial :
<span> 3.2 </span> Factoring <span> 3x3y6 - x3 + 6</span>
Try to factor this multi-variable trinomial using trial and error<span>
</span>Factorization fails
<span>Equation at the end of step 3 :</span><span> -y • (3x3y6 - x3 + 6) = 0
</span><span>Step 4 :</span>Theory - Roots of a product :
<span> 4.1 </span> A product of several terms equals zero.<span>
</span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span>
</span>We shall now solve each term = 0 separately<span>
</span>In other words, we are going to solve as many equations as there are terms in the product<span>
</span>Any solution of term = 0 solves product = 0 as well.
Solving a Single Variable Equation :
<span> 4.2 </span> Solve : -y = 0<span>
</span>Multiply both sides of the equation by (-1) : y = 0