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Ugo [173]
4 years ago
11

What is the slope that crosses through the point (-4,-5) and (6,8)

Mathematics
1 answer:
Angelina_Jolie [31]4 years ago
5 0
Slope = \frac{Y2 - Y1}{X2 - X1}

\frac{8 - (-5)}{6 - (-4)}

Your final answer is: \frac{13}{10}
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3 years ago
If f(2)=9 and f(-1)=14, write a linear function that fits this scenario. Be sure to use proper notation. HELP!!
olya-2409 [2.1K]

Answer:

The required linear function is: f(x) = $ \frac{-5}{3}x + \frac{37}{3} $

Step-by-step explanation:

We are given that f(x) is a linear function and it takes the value 9 when x = 2 and 14 when x = -1.

Now the general form of any linear function is: f(x) = ax + b.

Substituting these values in the general form we get:

f(2) = 9  = 2a + b

f(-1) = 14 = -a + b

Solving these two equations we get:

b = 37/3

Substituting this in the second equation to find 'a'.

a = -5/3

Therefore, the function f(x) = $ \frac{-5}{3} $x + $ \frac{37}{3} $.

4 0
3 years ago
I need help with Multiplication Properties of Exponents desperately!! I've tried to solve both problems repeatedly and I cannot
Yuliya22 [10]

Answer:

1) x= -36.

2) x = 0.

Step-by-step explanation:

1) Taking the 3rd power to both sides and using the following exponent law:

\left(a^b\right)^c = a^{bc}

we get:

\left(\left(m^{x}\right)^{\frac{1}{3}}\right)^3 = \left(m^{-12}\right)^3 \\ m^x = m^{-36}

So this tells us that x = -36.

2) We can distribute the power inside every term. So the left side becomes:

\left(3x^3y^x\right)^3 = 3^3\left(x^3)^3y^{3x} = 27x^9y^{3x}

Now, the trick here is to remember that y^0 = 1, so replacing 1 with y^0, which then gives us:

27x^9y^{3x} = 27x^9y^{0}, telling us that 3x = 0 and thus, x = 0.

7 0
4 years ago
Help me please and I will mark you brainlieess
Fudgin [204]

Answer:

10(3.14) = 31.4

20(3.14)=62.8

It will be twice the size

3 0
2 years ago
Solve the differential equation x^3y"'− 3x^2 y" 6xy'−6y = 0.
Anna [14]
<span>Equation at the end of step  1  :</span><span> (((x3)•y)-(((3x2•y6)•x)•y))-6y = 0 </span><span>Step  2  :</span><span>Step  3  :</span>Pulling out like terms :

<span> 3.1 </span>    Pull out like factors :

  <span> -3x3y7 + x3y - 6y</span>  =  <span> -y • (3x3y6 - x3 + 6)</span> 

Trying to factor a multi variable polynomial :

<span> 3.2 </span>   Factoring   <span> 3x3y6 - x3 + 6</span> 

Try to factor this multi-variable trinomial using trial and error<span> 

 </span>Factorization fails

<span>Equation at the end of step  3  :</span><span> -y • (3x3y6 - x3 + 6) = 0 </span><span>Step  4  :</span>Theory - Roots of a product :

<span> 4.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 4.2 </span>     Solve  :    -y = 0<span> 

 </span>Multiply both sides of the equation by (-1) :  y = 0 

3 0
3 years ago
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