Let "x" represent the number of units
5x = the number of tomato plants in Inessa's garden
6x = the number of tomato plants in Ralph's garden
the question says that half (1/2 x (5x)) of Inessa's tomato plants are taken from her garden and put into Ralph's garden
this means that Ralph has a total of 850 tomato plants in his garden
using all of this information, we get the following (which we have to solve):
(1/2)(5x) + 6x = 850
when we solve for "x", we find that:
"x" = 100
so, going back to the original statement, if Ralph started out with (6x) tomato plants, and "x" = 100, we have to multiply 6 by 100
doing so gives us our final answer:
Ralph had 600 tomato plants in the beginning
Question 23:
x = 4
DE = 44
Question 24:
x = 25
SE = 28
Step-by-step explanation:
As RS is the perpendicular bisector of DE, it will divide DE in two equal parts DS and SE
<u>Question number 23:</u>
Given
DS = 3x+10
SE = 6x-2
As the two segments are equal:

Subtracting 10 from both sides

subtracting 6x from both sides

Dividing both sides by -3

Now

And

<u>Question No 24:</u>
Given
DS = x+3
DE = 56
We know that:

So
DS = 
As DS is 28, SE will also be 28
Hence,
Question 23:
x = 4
DE = 44
Question 24:
x = 25
SE = 28
Keywords: Bisector, Line segment
Learn more about line segments at:
#LearnwithBrainly
Answer:
(e) 39
Step-by-step explanation:
The expected value (or the average number) of impulse purchases per day is given by the probability of an impulse purchase being made (6%) multiplied by the daily number of customers (650):

The average number of impulse purchases is 39 per day.
Assuming that you mean to put n instead of 5, this is demonstrating The Identity Property.
The identity property is the property that states that by adding 0 to a number, you don't change the value. For example, 510 + 0 = 510.
Answer:
y=7* (0.5)^x
Step-by-step explanation:
We are given that when x increases from 'a' to 'a+2' then y must increase by a factor of 1/4=0.25.
i.e. when x=a and x'=a+2.
then y/y=0.25 where y' is the function after putting x' to the old function.