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Marina CMI [18]
3 years ago
15

Tell whether each equation has one ,zero,or infinitely many solutions

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
The answer to the question

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The sum of 2 times a number and 3 is 6
barxatty [35]
Is there a question or is this it ?
it basically answers itself because 2 times 3 is 6
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3 years ago
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The value of 4 in 40 is how many times the value of 4 in 400
NikAS [45]
The value of 4 in 40 is 10 times less than the value of 4 in 400
7 0
2 years ago
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Please help out !!!!
evablogger [386]

Answer:

x  = 8

Step-by-step explanation:

you have similar triangles here

so     2 is to 4  as  4 is to x

2/4 =  4/x

x = 8

8 0
3 years ago
Can you please help me out with a question
Finger [1]

The standard equation of a circle is expressed as

(x - h)^2 + (y - k)^2 = r^2

where

h is the x coordinate of the center of the circle

k is the y coordinate of the center of the circle

r is the radius of the circle(the distance from the center of the circle to the circumference

From the graph,

h = - 1

y = 4

r = 5

By substituting these values into the equation, we have

(x - - 1)^2 + (y - 4)^2 = 5^2

(x + 1)^2 + (y - 4)^2 = 25

Thus, the equation of the circle is

(x + 1)^2 + (y - 4)^2 = 25

8 0
1 year ago
Two buses leave towns 304 miles apart at the same time and travel toward each other. One bus travels 14 mih slower than the othe
8090 [49]

Answer:

The faster bus moves at 83mi/h and the slower one moves at 69mi/h.

Step-by-step explanation:

Let's define:

R₁ = rate of bus 1, this is the faster one.

R₂ = rate of bus 2, this is the slower one.

We know that one bus travels 14mi/h slower, then:

R₂ = R₁ - 14mi/h.

Now we know that:

Distance = Speed*Time.

If we add the distances that both busses travel in 2 hours, it should be equal to the initial distance between the buses, then:

R₁*2h + R₂*2h = 304 mi

Then we have the two equations:

R₂ = R₁ - 14mi/h

R₁*2h + R₂*2h = 304 mi

The first step is to replace the first equation in the second one, to get:

R₁*2h + (R₁ - 14mi/h)*2h = 304 mi

And now we can solve this for R₁.

R₁*2h + R₁*2h - 14mi/h*2h = 304 mi

R₁*4h - 28mi = 304mi

R₁*4h = 304mi + 28mi = 332mi

R₁ = 332mi/4h = 83mi/h

The faster bus moves at 83mi/h

And we know that the slower one moves at 14mi/h slower than this, then:

R₂ = R₁ - 14mi/h = 83mi/h - 14mi/h = 69 mi/h

7 0
2 years ago
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