1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KonstantinChe [14]
3 years ago
6

What is the gcf of 42 and 60​

Mathematics
2 answers:
ivolga24 [154]3 years ago
4 0

Answer:

The GCF of 42 and 60 is 6

Step-by-step explanation:

42: 1,2,3,6,7,14,21,42

60: 1,2,3,4,5,6,10,12,15,20,30,60

Korolek [52]3 years ago
4 0

Answer:

6

Step-by-step explanation:

Factors of 42 = 1, 2, 3, 6, 7, 14, 21 and 42

Factors of 60 = 1 , 2 , 3 , 4 , 5 , 6 , 10 , 12 , 15 , 20 , 30 and 60

The highest factor which comes in both 42 and 60 is 6

You might be interested in
For which value of x must the expression square root of 19x be further simplified? A. 15. B 21. C 28. D 41
algol [13]
<span>The expression of the square root of 19x must be simplified when x is equal to 28. This is because possible factors of 28 can be seen to be 4 and 7, and 4 is a perfect square. This means it can be pulled outside of the square root when evaluated. The other options include only prime factors that could not be pulled out. (3,5), (3,7), (1,41)
   28 simplifies as such:
 Sqrt(19*28) = Sqrt(19*4*7) = 2*Sqrt(19*7) = 2*Sqrt(133).</span>
5 0
3 years ago
Read 2 more answers
Write the equation in standard form for the circle with center (5,0) passing through (-1, 9/2)
andreev551 [17]

Answer:

(x - 5)^2 + y^2 = 225/4,

or you could write it as (x - 5)^2 + y^2 = 56.25.

Step-by-step explanation:

The factor form is

(x - h)^2 + (y - k)^2 = r^2  where the center is (h, k) and r = the radius.

So we have:

(x - 5)^2 + (y - 0)^2 = r^2

As the point  (-1, 9/2) is on the line:

(-1 - 5)^2 +  (9/2)^2 = r^2

r^2 =  36 +  81/4

r^2 = 225/4.

So  substituting for r^2:

(x - 5)^2 + (y - 0)^2 = 225/4

(x - 5)^2 + y^2 = 225/4 is the standard form.

3 0
3 years ago
5x + 16 = 9x-4 plz solve
RSB [31]
*Answer:*
x = 5

*step-by-step solution*

5 0
3 years ago
Read 2 more answers
Clarissa got a part time job during the first week she earned $439.50. During the second and third week she worked a total of 62
iren2701 [21]

Answer:

$2063.44

Step-by-step explanation:

1st week = $439.50

2nd and 3rd week = 62 hours and each hour = $22.79

Total amount earned in 2nd and 3rd week = 62 * 22.79 = $1412.98

4th week = 48% of what she earned in her first week = 48% of $439.50

4th week = (48 / 100) * 439.50 = $210.96

Total amount she earned = 1st week + 2nd & 3rd week + 4th week

Total amount = $439.50 + $1412.98 + $210.96

Total amount = $2063.44

She earned a total of $2063.44

6 0
3 years ago
I need help with question number 12. Can’t figure this answer. Tried for 1 hour.
o-na [289]

Answer:

2, 12

Step-by-step explanation:

LCM = Least common multiple

LCM of 2 and 12 is 12

2 4 6 8 10 12

12

LCM of 6 and 8 is 24

6 12 18 24

8 16 24

LCM of 3 and 8 is 24

3 6 9 12 15 18 21 24

24

LCM of 12 and 24 is 24

12 24

24

5 0
3 years ago
Other questions:
  • Have no idea how to do 36, please help.
    12·1 answer
  • Does sin cos tan only work with right triangles
    13·1 answer
  • Please please help me with this
    5·1 answer
  • a real estate agent earns a commission of 4% of the selling price for each house he sells. How expensive of a house does he have
    5·1 answer
  • Sixteen of the 24 schools in Ryan's county are public schools. Ryan used this spinner to predict the probability that the winner
    15·1 answer
  • Help please due tonight
    6·1 answer
  • find the circumference of the circle shown below. Remember to use 3.14 for LaTeX: \piπ, and be sure to round your final answer t
    12·1 answer
  • Pls help me plssssssssssss
    10·1 answer
  • How would you go about solving for (3g - 25)(-5)?
    11·1 answer
  • Find the 11th term in the following geometric sequence.<br> -5,-10,-20,-40
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!