3 years ago

WILL MARK BRANLIEST, FOLLOW YOU, AND SAY UR THE BEST ON UR PROFILE

Mathematics

1 answer:

MAXImum [283]3 years ago

6 0

Question 1
*-24

question 2
*D

question 3
*B

question 4
*look at the picture

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What is the answer? X/8 - 4 = 15/16

sukhopar [10]

Answer:

Step-by-step explanation:

$\dfrac{x}{8}-4=\dfrac{15}{16}\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{x}{8\!\!\!\!\diagup_1}-(8)(4)=8\!\!\!\!\diagup^1\cdot\dfrac{15}{16\!\!\!\!\!\diagup_2}\\\\x-32=\dfrac{15}{2}\qquad\text{add 32 to both sides}\\\\x-32+32=7.5+32\\\\x=39.5$

5 0

4 years ago

The area of a blackboard is 1 1 third square yards. A poster's area is 8 over 9 square yards. What is the unit rate of the black

Darya [45]

Step-by-step explanation:

Given that,

The area of a blackboard is $1\dfrac{1}{3}=\dfrac{4}{3}\ \text{yards}^2$

The area of poster is $\dfrac{8}{9}\ \text{yards}^2$

We need to find the unit rate of the blackboard's area to the poster's area. So, it can be calcualted by dividing blackboard's area to the poster's area.

So,

$\dfrac{\dfrac{4}{3}}{\dfrac{8}{9}}=\dfrac{4}{3}\times \dfrac{9}{8}\\\\=1.5$