$6x^2-4x+1=6\left(x-\dfrac13\right)^2+\dfrac13\ge0$

which means the parabola lies above the x-axis over its entire domain. This means the area is given by

$\displaystyle\int_{-1}^2(6x^2-4x+1)\,\mathrm dx=2x^3-x^2+x\bigg|_{x=-1}^{x=2}=10-(-5)=15$

4 0

3 years ago

Let f(x)=1/x and g(x)=x^2-2. What is (fog)(-3)?

Elenna [48]

Answer:

Its value is 1/7.

I hope this will help you.

3 0

3 years ago

Which angle measures create a triangle with three different side lengths. 40°, 40°, and 100° 65°, 65°, and 65° 45°, 45°, and 90°

Gala2k [10]

Answer:

29°, 58°, and 93°

Step-by-step explanation:

If the angles opposite are equal, the sides are equal. In order to have three different side lengths, you must have <em>three different angles</em>.

8 0

2 years ago

I only have 2 more problems now

liq [111]

r° = 158°

s° = 180° - r° = 180° - 158° = 22°

4 0

3 years ago