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3 years ago

Which one is bigger 0.375 or 0.3(3)?

Mathematics

2 answers:

Crank3 years ago

7 0

Answer:

0.3(3)

Step-by-step explanation:

0.3(3) = 0.9>0.375 so 0.3(3)

Fofino [41]3 years ago

4 0

Answer:

Look at the tenths place (the first number after the decimal. The first number is a 3 and the other one is 2. 3>2. Therefore, 0.375 is bigger

Step-by-step explanation:

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Using a number 5 3 8 how can write nine proper fraction and nine improper fraction

beks73 [17]

You multiply 8 times 5 then add 3. So it's 43/8

7 0

3 years ago

Help me find the answer

elixir [45]

Answer:

y = - $\frac{1}{4}$ x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (4, - 4) ← 2 points on the line

m = $\frac{-4+3}{4-0}$ = - $\frac{1}{4}$

Note the line crosses the y- axis at (0, - 3) ⇒ c = - 3

y = - $\frac{1}{4}$ x - 3 ← equation of line

4 0

3 years ago

The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given

o-na [289]

Answer:

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

$D(q)=S(q)\\\\-6.10q^2-5q+1000=3.2q^2+10q-80$

Reorganize the terms in one side and reduce similar terms:

$3.2q^2+6.1q^2+5q+10q-80-1000=0\\\\9.3q^2+15q-1080=0$

that's a cuadratic equation, solve with the general formula when:

a=9.3, b=15, c=-1080

$q_{1}=\frac{-b+\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{1}=\frac{-15+\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{1}=\frac{-15+201}{18.6}\\\\q_{1}=\frac{186}{18.6}\\\\q_1=10$

q can't be negative because it is the quantity of bike frames, so:

$q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-15-\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{2}=\frac{-15-201}{18.6}\\\\q_{2}=\frac{-216}{18.6}\\\\$