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mezya [45]
3 years ago
12

Which one is bigger 0.375 or 0.3(3)?​

Mathematics
2 answers:
Crank3 years ago
7 0

Answer:

0.3(3)

Step-by-step explanation:

0.3(3) = 0.9>0.375 so 0.3(3)

Fofino [41]3 years ago
4 0

Answer:

Look at the tenths place (the first number after the decimal. The first number is a 3 and the other one is 2. 3>2. Therefore, 0.375 is bigger

Step-by-step explanation:

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Graph the line y=kx+1 if it is known that the point M belongs to it: m(1,3)
Novosadov [1.4K]

Answer:

y = 2x +1

Step-by-step explanation:

y=kx+1

Substitute the point into the equation

3 = k(1) + 1

3 = k+1

Subtract 1 from each side

3-1 = k

2 = k

y = 2x +1

The slope is 2 and the y intercept is 1

3 0
3 years ago
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This figure represents a compartment in a container for storing office supplies. Another compartment is identical except that it
postnew [5]

Answer:

140cm³

Step-by-step explanation:

Credit: yaretzigutierrez50

3 0
2 years ago
Find the measure of an angle between 0º and 360º coterminal with an angle of –110º in standard position
kondor19780726 [428]
<h2>Answer:</h2>

An angle measures how how much you have to rotate one line called <em>initial side</em> so it lies on the top of other line called the <em>terminal side. </em>Angles whose vertex is located at the origin having the initial side on the positive x-axis is said to be in standard position. On the other hand, coterminal angles are angles in standard position having the same terminal side. In this way, for the angle:

-110^{\circ} \\ \\ Its \ coterminal \ is: \\ \\ \alpha=360^{\circ}-110^{\circ}=\boxed{250^{\circ}}

3 0
3 years ago
PLEASE HELP (30 POINTS) Solve the rational equation x/3 = x^2/x + 5 , and check for extraneous solutions.
anygoal [31]

Option C: x=0 and x=\frac{5}{2} are the solutions.

Explanation:

The equation is \frac{x}{3} =\frac{x^{2} }{x+5}

We shall determine the value of x, by simplifying the equation.

$\begin{aligned} x(x+5) &=3 x^{2} \\ x^{2}+5 x &=3 x^{2} \\ 2 x^{2}-5 x &=0 \\ x(2 x-5) &=0 \end{aligned}$

Thus, x=0 and x=\frac{5}{2} are the solutions.

Now, let us check whether the solutions are extraneous solutions.

Let us substitute x=0 in the original equation to check whether both sides of the equation are equal.

\begin{aligned}&\frac{0}{3}=\frac{0^{2}}{0+5}\\&0=\frac{0}{5}\\&0=0\end{aligned}

Thus, both sides of the equation are equal.

Hence x=0 is a true solution.

Now, Let us substitute x=\frac{5}{2} in the original equation to check whether both sides of the equation are equal.

\begin{aligned}\frac{\left(\frac{5}{2}\right)}{3} &=\frac{\left(\frac{5}{2}\right)^{2}}{\left(\frac{5}{2}\right)+5} \\\frac{5}{6} &=\frac{\left(\frac{25}{4}\right)}{\left(\frac{15}{2}\right)} \\\frac{5}{6} &=\frac{5}{6}\end{aligned}

Thus, both sides of the equation are equal.

Hence, x=\frac{5}{2} is a true solution.

Thus, solutions are not extraneous.

Hence, Option C is the correct answer.

8 0
3 years ago
Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th
alexandr1967 [171]

I'm guessing the function is

f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}

which, split into partial fractions, is equivalent to

\dfrac1{x-6}-\dfrac1{x+2}

Recall that for |x| we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

With some rearranging, we find

\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n

valid for \left|\dfrac x6\right|, or |x|, and

\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n

valid for \left|-\dfrac x2\right|, or |x|.

So we have

f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n

f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)

f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n

Taken together, the power series for f(x) can only converge for |x|, or -2.

6 0
3 years ago
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