All categories

3 years ago

Need help fast, being timed!!

Mathematics

1 answer:

tamaranim1 [39]3 years ago

4 0

Answer:

Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.

Step-by-step explanation:

From given scatter plot, we see that upper quartile of Mrs. Cai's class = 4

lower quartile of Mr. Roland’s class = 4

Both are equal so that means.

That means Mr. Roland’s class was more successful because his class’s lower quartile was the same as Mrs. Cai’s class’s upper quartile.

Hence last choice is correct.

You might be interested in

Solve the following system<br> algebraically:

Basile [38]

Answer: A (8,4)

Step-by-step explanation:

X=8

2x+y=20

2(8)+y=20

16 +y = 20

Y= 4

(8,4)

3 0

3 years ago

Read 2 more answers

Which number<br> is between 2.23 and 2.24 on a number line?

Gekata [30.6K]

Answer:

There are infinity many numbers between 2.23 an 2.24, but if you want the exact middle, it's 2.235

Hope this helped :)

8 0

3 years ago

Read 2 more answers

Find the missing term or terms in each arithmetic sequence.

bezimeni [28]

Answer:

I believe the terms would be 31, 35, 39.

Step-by-step explanation:

We know this because 43-27 is 16. since there are 3 terms missing, we divide the answer by 4, and you get 4. The number you get there is how many you add to each term to get the missing ones. For example, 27+4=31. The pattern is adding 4 to each term. Hope I helped!

5 0

2 years ago

Read 2 more answers

Use green's theorem to compute the area inside the ellipse x252+y2172=1. use the fact that the area can be written as ∬ddxdy=12∫

Pavel [41]

The area of the ellipse $E$ is given by

$\displaystyle\iint_E\mathrm dA=\iint_E\mathrm dx\,\mathrm dy$

To use Green's theorem, which says

$\displaystyle\int_{\partial E}L\,\mathrm dx+M\,\mathrm dy=\iint_E\left(\frac{\partial M}{\partial x}-\frac{\partial L}{\partial y}\right)\,\mathrm dx\,\mathrm dy$

( $\partial E$ denotes the boundary of $E$ ), we want to find $M(x,y)$ and $L(x,y)$ such that

$\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1$

and then we would simply compute the line integral. As the hint suggests, we can pick

$\begin{cases}M(x,y)=\dfrac x2\\\\L(x,y)=-\dfrac y2\end{cases}\implies\begin{cases}\dfrac{\partial M}{\partial x}=\dfrac12\\\\\dfrac{\partial L}{\partial y}=-\dfrac12\end{cases}\implies\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1$

The line integral is then

$\displaystyle\frac12\int_{\partial E}-y\,\mathrm dx+x\,\mathrm dy$

We parameterize the boundary by

$\begin{cases}x(t)=5\cos t\\y(t)=17\sin t\end{cases}$

with $0\le t\le2\pi$ . Then the integral is

$\displaystyle\frac12\int_0^{2\pi}(-17\sin t(-5\sin t)+5\cos t(17\cos t))\,\mathrm dt$

$=\displaystyle\frac{85}2\int_0^{2\pi}\sin^2t+\cos^2t\,\mathrm dt=\frac{85}2\int_0^{2\pi}\mathrm dt=85\pi$

###

Notice that $x^{2/3}+y^{2/3}=4^{2/3}$ kind of resembles the equation for a circle with radius 4, $x^2+y^2=4^2$ . We can change coordinates to what you might call "pseudo-polar":