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3 years ago

8

As a business person you need to visit each of the following cities once. You need to start in Atlanta and end in Atlanta. Use t

he "Nearest Neighbor" Algorithm to find one of the cheaper routes to visit each city and return home again.
Group of answer choices

A

B

C

D

2 answers:

SIZIF [17.4K]3 years ago

8 0

Answer:

it was B

Step-by-step explanation:

vredina [299]3 years ago

3 0

Answer:

I say its A

Step-by-step explanation:

You might be interested in

This table shows values represented by an exponential function.

Bad White [126]

Answer:

$a = 2 , f(2)=9$

$b = 4 , f(4)=64$

And replacing the data into the average rate formula we got:

$m = \frac{64-9}{4-2}= 27.5$

And then the best answer for this case would be:

C. 27.5

Step-by-step explanation:

For this cae we know that the average rate of change of a function is given by this general expresion:

$m = \frac{f(b) -f(a)}{b-a}$

For this special case from the info of the table we have:

$a = 2 , f(2)=9$

$b = 4 , f(4)=64$

And replacing the data into the average rate formula we got:

$m = \frac{64-9}{4-2}= 27.5$

And then the best answer for this case would be:

C. 27.5

7 0

3 years ago

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago

If a quadratic equation has a real root, what do you know about the other roots of the equation? Explain.

notsponge [240]

Answer:

A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:

1) The other root is also a real number, but a different number

2) Its a repeated root, so the other root is the same number.

The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.

Following are 3 possibilities for the roots of a quadratic equation:

2 Real and Distinct roots
2 Real and Equal roots
2 Complex roots

7 0

3 years ago

Y-intercept: (0,<br> y=-2x2 – 16x – 34<br> What is the y intercept?

tekilochka [14]

Answer: Solve for Y

y = -16x - 38

And then y intercept is

(0, -38)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

The radius of the circle is 3 millimeters. what is the circles area

Irina18 [472]

Answer:

28.26 millimeters

4 0

3 years ago