Answer: 423
Step-by-step explanation:
Answer:
Kindly check explanation
Step-by-step explanation:
The hypothesis :
H0 : μ1 = μ2
H1 : μ1 > μ2
Given :
x1 = 21.1 ; n1 = 53 ; s1 = 1.1
x2 = 20.7 ; n2 = 46 ; s2 = 1.2
The test statistic :
(x1 - x2) / √[(s1²/n1 + s2²/n2)]
(21.1 - 20.7) / √[(1.1²/53 + 1.2²/46)]
0.4 / 0.2326682
Test statistic = 1.719
The degree of freedom using the conservative method :
Comparing :
Degree of freedom = n - 1
Degree of freedom 1 = 53 - 1 = 52
Degree of freedom 2 = 46 - 1 = 45
Smaller degree of freedom is chosen ;
The Pvalue from Test statistic, using df = 45
Pvalue = 0.0462
Pvalue < α ; Hence, there is significant evidence to conclude that average age of Gorka student is higher than Yaphoa.
Answer:
Just calculate it. It is very easy.
1995 = x
1996 = x + 0.62
1997 = x + 0.62 + 0.29
x + x + 0.62 + x + 0.62 + 0.29 = 11.25
3x + 1.53 = 11.25
3x = 11.25 - 1.53
3x = 9.72
x = 9.72 / 3
x = 3.24 <== 1995 = 3.24 million
1996 = 3.24 + 0.62 = 3.86 million <==
1997 = 3.24 + 0.62 + 0.29 = 4.15 million <==
