To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)
Answer:
Use pemdas
Step-by-step explanation:
Paranthese, e, multiplacation, division, addition, subtraction
Answer:
22 units
Step-by-step explanation:
11 - (-11) = 22
Answer:
Step-by-step explanation:
the standard equation of a line is in the form y=mx+b where m is the slope and b is the y intercept so if m = 1/4 and b = -3/4 you can just replace those spots giving you y=1/4x+-3/4
