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Firdavs [7]
3 years ago
12

The perimeters of the square and the triangle shown below are equal. What is the value of x?

Mathematics
1 answer:
Rudiy273 years ago
8 0
Perimeter is the sum of all the sides. So we can set up an equation:

\sf 3x+1+3x+1+3x+1+3x+1=2x+8+x+8+4x+2

Now solve for 'x', combine like terms:

When it comes to terms with variables it's just like normal addition but we keep the variable:

\sf 3x+3x+3x+3x=12x
\sf 2x+x+4x=7x

So we have:

\sf 12x+1+1+1+1=7x+8+8+2

Add:

\sf 12x+4=7x+18

Subtract 7x to both sides:

\sf 5x+4=18

Subtract 4 to both sides:

\sf 5x=14

Divide 5 to both sides:

\boxed{\sf x=2.8}
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The daltons completed 30% of their 2140-mile trip the first day
Ugo [173]
To figure out how many miles the Daltons traveled the first day you times 2140 miles and 30 percent.
So 2140 x .30 = 642
They traveled 642 miles the first day.

To figure out how many miles they still have to travel you subtract your original miles (2140) from how many miles they have already traveled (642).
So 2140 - 642 = 1498
They have 1498 miles to still travel.
4 0
3 years ago
Read 2 more answers
The difference between two numbers is 15. If 8 is added to twice the greater number, the result is 4 less than 3 times the lesse
yuradex [85]

Answer:


Step-by-step explanation:

Let x be the greater number and y be the smaller number. We know that their difference is 15, so we have

x-y=15

Then, we have the following information: if we add twice the greater (2x) and 8 (2x+8), the result is 3 times the lesser (3y) minus four (3y-4). So, we have

2x+8 = 3y-4 \iff 2x-3y = -12

So, we have the follwing system:

\begin{cases} x-y=15\\2x-3y = -12\end{cases}

From the first equation, we can derive x = y+15, and substitute this expression in the second equation to get

2(y+15)-3y = -12 \iff 2y + 30 -3y = -12 \iff -y = -42 \iff y = 42

Substitute this value for y in the first equation to get

x-42=15 \iff x=15+42 \iff x = 57

8 0
3 years ago
PQ is rotated 180 degrees clockwise about P. What are the coordinates of P' and Q'?
Salsk061 [2.6K]

The co ordinates of P' is (-7,-2) and Q' is (-16, -8)

<u><em>Explanation</em></u>

PQ is rotated 180 degrees clockwise about P. It means <u>P and P' are the same points</u>.

According to the graph, the coordinates of P is (-7, -2) and  Q is (2, 4)

When PQ is rotated 180 degrees clockwise about P, then <u>P or P' will be the mid-point of Q and Q' </u>

Suppose, the co ordinate of Q' is (x, y)

Now according to the mid-point formula, the coordinate of P or P' will be: (\frac{x+2}{2},\frac{y+4}{2}) , which is actually at (-7, -2)

Thus.....

\frac{x+2}{2}=-7\\ \\ x+2=-14\\ \\ x= -16\\ \\ and\\ \\ \frac{y+4}{2}= -2\\ \\ y+4= -4\\ \\ y= -8

So, the co ordinates of P' is (-7,-2) and Q' is (-16, -8)

6 0
3 years ago
HELPP MEE PLEASEEE I DONT WANNA FAIL SUMMER SCHOOL NO FILES OR LINKS WOULD BE DEEPLY APPRECIATED
Artemon [7]
1.) 3.5% * 500 = 17.5

2.) 70.0% * 50 = 35.0

3.) 25.0% * 440 = 110.0

4.) 10.0% * 46 = 4.6
8 0
3 years ago
Given H = f(t) where H is the height in meters of an object and t is the time in
timama [110]

Answer:

D

Step-by-step explanation:

Well, since t = time in air, we already know that it traveled 2 seconds.

H = height in meters, and H = 18

So, after 2 seconds the object is 18m in the air

So, option D

4 0
1 year ago
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