A(n) = –3 • 2⁽ⁿ⁻¹⁾
for n = 1 , A₁ = -3.(2)⁰ = -3
for n = 2 , A₂ = -3.(2)¹ = -6
for n = 3 , A₃ = -3.(2)² = -12
for n = 4 , A₄ = -3.(2)³ = -24
...........................................
for n = 8 , A₈ = -3.(2)⁷ = -384
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then
By substitution, we have that
and
.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
P in terms of V is:
P = 432/V
Step-by-step explanation:
We know that y varies inversely as x, we get the equation
y ∝ 1/x
y = k/x
k = yx
where k is called the constant of proportionality.
In our case,
P is inversely proportional to V
Given
P = 18
V = 24
so
P = k/V
k = PV
substituting P = 18 and V = 24 to determine k
k = 18 × 24
k = 432
now substituting k = 432 in P = k/V
P = 432/V
Therefore, P in terms of V is:
P = 432/V
Answer:
28
Step-by-step explanation:
I guessed it right on hegarty maths and this was the answer
Answer:
ok so the earth radius is 1534mi so if that is the radius than the area is 7.39×10^6so then you divide that into 3 pieces so each piece would be 2,463,333.3333 the nearest million would be 2,000,000
Step-by-step explanation:
