Question

What is the length (magnitude) of the vector (5,-2)?

Answer 1

Answer:

The magnitude of the given vector is $\sqrt{29}$.

Step-by-step explanation:

The magnitude of a vector v=<a,b> is defined as

$|v|=\sqrt{a^2+b^2}$

The given vector is

$v=$

The magnitude of the given vector is

$|v|=\sqrt{5^2+(-2)^2}$

$|v|=\sqrt{25+4}$

$|v|=\sqrt{29}$

Therefore the magnitude of the given vector is $\sqrt{29}$.

Answer 2

5^2+(-2)^2=29
magnitude=(29)^(1/2)=around 5.3852