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skad [1K]
3 years ago
9

5/6k=1/6 solve for k

Mathematics
2 answers:
Molodets [167]3 years ago
7 0
5/6k = 1/6
k = 1/6 / 5/6 = 1/6 * 5/6                after you multiply your solution for K = 1/5           
Artyom0805 [142]3 years ago
3 0
Multipy both sides by 6/5
(6/5)*(5/6k)=(6/5)*(1/6)
K=1/5
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Bas_tet [7]

Answer:

5

Step-by-step explanation:

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3 years ago
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2−(−4)+3+(−6)−(−2)2, minus, left parenthesis, minus, 4, right parenthesis, plus, 3, plus, left parenthesis, minus, 6, right pare
Yuki888 [10]

Answer: 7

Step-by-step explanation:

2−(−4)+3+(−6)−(−2)2

solution:

– x – = +

– x + = –

= 2−(−4)+3+(−6)−(−2)2

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3 years ago
The function H(t) = −16t2 + 75t + 25 shows the height H(t), in feet, of a baseball after t seconds. A second baseball moves in t
sasho [114]
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Consider the function f(x) = x3 − 4x2 + 2. Calculate the limit of the difference quotient at x0 = 3 for f(x).
m_a_m_a [10]
<h2>Part 1.</h2>

Answer: \boxed{f'(x)=3x^2-8x}

The limit of the difference quotient is simply the derivative, so we can express this as follows:

f'(x)=\underset{\Delta x\rightarrow0}{lim}\frac{\triangle y}{\Delta x}=\frac{f(x+\Delta x)-f(x)}{\Delta x}

So our function is:

f(x)=x^3-4x^2+2

Taking the derivative, we have:

f'(x)=3x^2-8x

So the correct option is:

\boxed{f'(x)=3x^2-8x}

<h2>Part 2.</h2>

Answer: \boxed{y=3x-16}

The equation of the line that passes through the same point can be found as:

y-y_{0}=m(x-x_{0})

Where x_{0}=3, so we need to find y_{0}. Plug in that x-value in the function we have:

y_{0}=f(3)=(3)^3-4(3)^2+2 \\ \\ y_{0}=-7 \\ \\ \\ So \ the \ point \ is: \\ \\ P(x_{0},y_{0})=(3,-7)

And the slope is:

m=f'(3)=3(3)^2-8(3) \\ \\ m=3

Then, the equation of the line is:

y-(-7)=3(x-3) \\ \\ \therefore y+7=3x-9 \\ \\ \boxed{y=3x-16}

<h2 /><h2>Part 3.</h2>

Answer: Shown below

As you can see below, the graph of the function of f is continuous. This is so because we have plotted a polynomial function whose domain is the set of all real numbers. So the function is defined at the point P(3,-7), so the derivative exists at this point, hence we can calculate a tangent line there. In conclusion, we get the graph shown below. The blue line is the tangent line while the red curve is the graph of f

3 0
3 years ago
Check answer now asap
kakasveta [241]

Answer:

∠ A ≅ ∠ E

∠ K = 60°

Step-by-step explanation:

Part 1.

Given that ABCD ≅ EFGH.

Whenever a quadrilateral is congruent to another, and we write the congruency in symbol, then the order of congruency with respect to angles and sides are maintained in the symbol.

That means if ABCD ≅ EFGH, then ∠ A ≅ ∠ E, ∠ B ≅ ∠ F and so on.

Therefore, in this case, ∠ A ≅ ∠ E (Answer) {It is also shown in the diagrams}

Part 2.

Given that, Δ EFG ≅ Δ KLM

Hence, ∠ E ≅ ∠K, ∠ F ≅ ∠ L, and ∠ G ≅ ∠ M

It is also given that ∠ F = 35° and ∠ G = 85°

So, ∠ E = 180° - ∠ F - ∠ G = 180° - 85° - 35° = 60°

Since, ∠ E = ∠ K,

So, ∠ K = 60°. (Answer)

7 0
4 years ago
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