Which of the following is the correct action to take when simplifying the expression (x^3)^5

Can someone tell me if I did this right? If it's wrong can you tell me how to do it step by step? Thanks

Lesechka [4]

Hi there!

So first off, here are little definitions you need to know in order to be able to answer your question :

Constant means that the rates of change are the same.

Variable means that the rates of change are different.

But from what I can see, you don't even need those definitions because you got both answers right!

Continue your great work! If there's anything just let me know! :)

6 0

3 years ago

Ys is the perpendicular bisector of xz. What is the length of Xs if xz is 18 inches long?

exis [7]

Answer:

XS is 9 inches long.

Step-by-step explanation:

Given that

YS is the perpendicular bisector of XZ.

Length of XZ = 18 inches

To find:

Length of XS = ?

Solution:

First of all, let us learn about the perpendicular bisector.

Perpendicular bisector of a line AB is a line PQ, which divides the line AB in two equal parts and is at an angle of $90^\circ$ with the line AB.

If B is on the line PQ, then $BP = BQ = \frac{PQ}{2}$ and

$\angle ABP = \angle ABQ = 90^\circ$

Applying the above property in our given question.

Kindly refer to the attached image for the given dimensions.

S is on the line XZ.

$XS = SZ = \frac{XY}{2} = \dfrac{18}{2} \\\Rightarrow \bold{XS = 9\ inches}$

So, the answer is XS is 9 inches long.

8 0

3 years ago

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th

ehidna [41]

Question:

In 2002, the Centers for Disease Control and Prevention (CDC) reported that 8% of women married for the first time by their 18th birthday, 25% married by their 20th birthday, and 76% married by their 30th birthday. Based on these data, what is the probability that in a family with two daughters, the first and second daughter will be married by the following ages? (Enter your answers to four decimal places.) (a) 18 years of age (b) 20 years of age (c) 30 years of age

Answer:

A.) 0.0064

B.) 0.0625

C.) 0.5776

Step-by-step explanation:

Given the following :

Married by 18th birthday = 8% = 0.08

Married by 20th birthday = 25% = 0.25

Married by 30th birthday = 76% = 0.76

In a family with two(2) daughters :

P(First daughter will be married by 18) = 0.08

P(second daughter will be married by 18) = 0.08

P(1st and 2nd married by 18) = (0.08×0.08) = 0.0064

B.)

P(First daughter will be married by 20) = 0.25

P(second daughter will be married by 20) = 0.25

P(1st and 2nd married by 20) = (0.25×0.25) = 0.0625

C.)

P(First daughter will be married by 30) = 0.76

P(second daughter will be married by 30) = 0.76

P(1st and 2nd married by 30) = (0.76×0.76) = 0.5776

6 0

3 years ago

Lianne charged twice as much to walk a large dog than she did to walk a small dog. This week she had time to was 10 small dogs a

guapka [62]

Well she charged twice as much to walk large then small. Let s be small and l be large.
We we know that
l = 2s

we also know that she wants to make 100 so
xl + ys = 100

Where where x is number of large and y is number of small. it says she walked 10 small and 5 large so
5l + 10s = 100

substitute 2s for l because they are same value as shown in first equation I made
5 (2s) + 10s = 100
10s + 10s = 100
20s = 100
s = 5

we can now solve for l
l = 2s
l = 2 * 5
l = 10

So s is 5 and l is 10.

4 0

3 years ago

If the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20

zysi [14]

Answer:

Therefore, we conclute that the map distance between A and C is 35 m.u..

Step-by-step explanation:

We know that the order of three loci is A B C, and the map distance between A and B is 15 m.u., and the map distance between B and C is 20 m.u. We calculate the map distance between A and C.

Therefore, we get

$AC=AB+BC\\\\AC=15+20\\\\AC=35\\$

Therefore, we conclute that the map distance between A and C is 35 m.u..

4 0

3 years ago