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vladimir1956 [14]
3 years ago
11

Is 28 a solution to the inequality you wrote in Exercise 3? How do you know?

Mathematics
1 answer:
Evgen [1.6K]3 years ago
6 0

Answer:

Yes

Step-by-step explanation:

s<30

Put in 28 for s

28<30

Twenty eight is less than 30 so it is a solution

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what is the algebraic equation 3 times the sum of a number and 7 is 2 less than five times the number
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Let n = number

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3 2/7 minus (1 6/7 +2/5) =
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First, let's make all the mixed fractions into improper fractions. To do that, we multiply the whole number by the denominator and add the numerator; this new number becomes the numerator while we keep the same denominator, thus:

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Our new problem is

23/7 - (13/7 + 2/5)

The next step to be able to simplify this is to have common denominators. To do that here, we will multiply the first two fractions by 5/5 and the third fraction by 7/7, thereby making all three fractions have a denominator of 35:

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