A 755 N diver drops from a board 10.0 m above the water’s surface. Find

1 answer:

5 0

F = 755N, and h = 10.0 m and a = 9.8 m/s^2 and m =? and v = ?To find the mass use F = ma 755 = (m)(9.8) and m = .77 kg then use the formula KE + PE = PE2 + KE2 which is 1/2mv2 + mgh = mgh(2) + 1/2mv2 (2) to solve for the velocity. v1 = 0 and h1 = 10 and v2 = ? and h2 = 0 (1/2)(.77)(0^2) + (.77)(9.8.)(10) = (1/2)(.77)(V2^2) + (.77)(9.8)(0)v=14 m/s

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What is the average rate of change of the function f(x)=20(14)xf(x)=20(14)x from x = 1 to x = 2? Enter your answer, as a decimal

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The average rate of a function f(x) over an interval x = a and x = b is given by:

$Average \ Rate \ of \ Change= \frac{f(b)-f(a)}{b-a}$

Given the function

$f(x)=20(14)^x$

The average rate of change from x = 1 to x = 2 is given by:

$\frac{f(2)-f(1)}{2-1} = \frac{20(14)^2-20(14)^1}{1} \\ \\ =20(196-14)=20(182)=3,640$