Answer: -2.5,, -0.9,, -1/3,, 1.7,, 27/4
Step-by-step explanation:
Answer:
6x+21
Step-by-step explanation:
Remember that
If the given coordinates of the vertices and foci have the form (0,10) and (0,14)
then
the transverse axis is the y-axis
so
the equation is of the form
(y-k)^2/a^2-(x-h)^2/b^2=1
In this problem
center (h,k) is equal to (0,4)
(0,a-k)) is equal to (0,10)
a=10-4=6
(0,c-k) is equal to (0,14)
c=14-4=10
Find out the value of b
b^2=c^2-a^2
b^2=10^2-6^2
b^2=64
therefore
the equation is equal to
<h2>(y-4)^2/36-x^2/64=1</h2><h2>the answer is option A</h2>
Find the slope of the line connecting (1990,435000) and (2005,482300):
482300-435000 47300
m = ----------------------- = ---------------- = 3153/yr (approx)
2005 - 1990 15 yr
Use the point-slope formula to find the equation of this str. line:
y-435000 = (3153/yr)(x-1990)
The year 2020 is 30 years after 1990. Thus, the expected pop in 2020 is
given by y-435000 = 3153(30) = 94590, so that y = 529590.
