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Grace [21]
3 years ago
5

How did you find it and what is the anwser

Mathematics
1 answer:
Ray Of Light [21]3 years ago
5 0
This is fairly simple
multiply the number by 10 until there is no decimal
then put the number over that
13008/1000
Now simplify
1626/125 
OR
13 1/125
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What property is shown in the equation below?
shutvik [7]
The answer to the problem is B.
7 0
3 years ago
How does the graph of g(x) = (x − 2)3 + 6 compare to the parent function of f(x) = x3?
Svet_ta [14]

The graph of g(x) is the graph of f(x) translated 2 units to the right and 6 units up.

<h3>How does the graph of g(x) compare to the one of f(x)?</h3>

Here we have:

f(x) = x^3\\\\g(x) = (x - 2)^3 + 6

You can notice that if we take f(x), and we shift it 2 units to the right, we have:

g(x) = f(x - 2)

Then if we apply a shift upwards of 6 units, then we have:

g(x) = f(x - 2) + 3

Replacing f(x) by the cubic parent function, we have:

g(x) = (x - 2)^3 + 6

So we conclude that the graph of g(x) is the graph of f(x) translated 2 units to the right and 6 units up.

If you want to learn more about translations:

brainly.com/question/24850937

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7 0
2 years ago
A community group is setting up 616 chairs in 22 equal rows for an
alexandr1967 [171]

Answer:

im sorry i do not know

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A particle moves on the hyperbola xy=18 for time t≥0 seconds. At a certain instant, y=6 and dydt=8. What is x that this instant?
professor190 [17]

Answer:

The value of x at this instant is 3.

Step-by-step explanation:

Let x\cdot y = 18, we get an additional equation by implicit differentiation:

x\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (1)

From the first equation we find that:

x = \frac{18}{y} (2)

By applying (2) in (1), we get the resulting expression:

\frac{18}{y}\cdot \frac{dy}{dt}+y\cdot \frac{dx}{dt} = 0 (3)

y\cdot \frac{dx}{dt}=-\frac{18}{y}\cdot \frac{dy}{dt}

\frac{dx}{dt} = -\frac{18}{y^{2}} \cdot \frac{dy}{dt}

If we know that y = 6 and \frac{dy}{dt} = 8, then the first derivative of x in time is:

\frac{dx}{dt} = -\frac{18}{6^{2}} \cdot (8)

\frac{dx}{dt} = -4

From (1) we determine the value of x at this instant:

x\cdot \frac{dy}{dt} = -y\cdot \frac{dx}{dt}

x = -y\cdot \left(\frac{\frac{dx}{dt} }{\frac{dy}{dt} } \right)

x = -6\cdot \left(\frac{-4}{8} \right)

x = 3

The value of x at this instant is 3.

4 0
3 years ago
Complete the following proof given &lt;1 =&lt;4 ; &lt;4 and &lt;5 form a linear pair prove: &lt;1 and &lt;5 are supplementary
Mandarinka [93]
Given taken given taken given taken given and then taken because that’s how the pattern is on the chart
4 0
3 years ago
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