Answer:the first ans (f(x)=(1/x+2)+3
Step-by-step explanation:
Answer:
B.
Step-by-step explanation:

Answer:
This function represents a direct variation because it passes through the origin and has a constant rate
Answer:
C) 100 m^2
Step-by-step explanation:
Area of a trapezoid= h*[(b1+b2)/2]
h=10
b1=8
b2=12
Therefore:
A=10*[(8+12)/2]
A=10*(20/2)
A=10*10
A=100
So the area of the trapezoid is 100 m^2
1. A quadratic equation has the following form: ax²+bx+c.
2. The leading coefficient is the number that is attached to the variable with the highest exponent. Then, the "a" is the leading coefficient of the quadratic equation.
3. The problem says that the leading coefficient is 1 (a=1) and the roots of the quadratic equation are 5 and -3. Then, you have:
(x-5)(x+3)=0
4. When you apply the distributive property, you obtain:
x²+3x-5x-15=0
x²-2x-15=0
5. Therefore, the answer is:
x²-2x-15=0