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3 years ago

Solve -x^2(x-2)(x-5)^3

Mathematics

1 answer:

ahrayia [7]3 years ago

7 0

Answer: = -x^6 + 17x^5 - 105x^4 + 275x^3 - 205x^2

Step-by-step explanation:

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-8 over -2 by the power of three Minus 3 times -2 times 4

Crazy boy [7]

Answer:88

Step-by-step explanation:

You can simplify -8/-2 its 4 then take 4 to the 3rd power and you'll get 64 the take 3×-2 and you'll get -6 then multiply -6×4 and you'll get -24 then subtract 64 - (-24) which would end up being plus a positive and you'll get 88

4 0

3 years ago

How many solutions are there to the equation below?

Art [367]

Answer: B.Infinitely many

3 0

3 years ago

the length of a rectangle is 50 feet less than its width. If the perimeter of the field is 840 feet, find the length of the fiel

LiRa [457]

$look\ at\ the\ picture\\\\2a+2(a-50)=840\\\\2a+2a-100=840\\\\4a-100=840\ \ \ /+100\\\\4a=940\ \ \ \ /:4\\\\a=235\ (ft)\\\\a-50=235-50=185\ (ft)\\\\Answer:lenght=185\ ft;\ width=235\ ft.$

8 0

3 years ago

Can someone help me with this thanks

Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

$\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}$

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

$\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}$

$\frac{BC}{sinA}=\frac{AB}{sinC}$

$\frac{2}{sin25}=\frac{3}{sinC}$

$\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )$

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

$\frac{BC}{sinA}=\frac{AC}{SinB}$

$\frac{2}{sin25}=\frac{l}{sin(115.66)}$

$l=\frac{2\times sin(115.66)}{sin25}$

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

#SPJ1

8 0

2 years ago

If 48% of the students in a certain college are female and there are 1440 female students, what is the total number of students

Andrews [41]

Answer:

3000 students

Step-by-step explanation:

If 48% of the students are female, and there are 1440 female students, we can set up a percentage proportion, assuming x is the total amount of students.

$\frac{1440}{x} = \frac{48}{100}$

We can use the cross products property to find the value of x.

$1440\cdot100=144000\\\\144000\div48=3000$

Hope this helped!

5 0

3 years ago