Answer:
When quantities have the same relative size. when they have the same ratio.
Step-by-step explanation:
pliz mark brainliest
Answer:
x = 3
Step-by-step explanation:
Since the angle at the vertex is bisected then the following ratio is true
= 
, that is
= ( cross- multiply )
4(9x - 9) = 3(6x + 6) ← distribute parenthesis on both sides
36x - 36 = 18x + 18 ( subtract 18x from both sides )
18x - 36 = 18 ( add 36 to both sides )
18x = 54 ( divide both sides by 18 )
x = 3
Answer:
0.703
Step-by-step explanation:
19/70 = 70.37/100
Hope This Helps :)
Note that <span>x^2+y^2=16x−26y−133 represents a circle.
x^2 - 16x + y^2 + 26y = 133
x^2 - 16x + 64 - 64 + y^2 + 26y + 169 - 169 = 133 (completing the square)
Then (x-8)^2 - 64 + (y+13)^2 - 169 = 133
Simplifying, (x-8)^2 + (y+13)^2 = 133 + 169 + 64 = 366
This circle acts as a constraint on the value of 6x-8y. Assume that x and y are both on the circle. Just supposing that x = 10, find y:
(10-8)^2 + (y+13)^2 = 366, or 4 + (y+13)^2 = 366, or (y+13)^2 = 362
This is a quadratic equation that could be solved for y, and the result(s) could be subst. into the expression 6x-8y.
If you were to repeat this exercise several times, for different values of x, you'd come up with various values of 6x-8y and in that way approach (if not find) a definite answer to "</span><span>Given that x2+y2=16x−26y−133, what is the biggest value that 6x−8y can have?"
Hope someone else can come up with a more elegant approach.</span>
Your answer should be D, 163, hope this helps! :D
