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Nikitich [7]
3 years ago
12

How to find a volume to a rectangular box

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0
You do length times width times height!
topjm [15]3 years ago
3 0
You multiply length times width times height. 
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Anwers : <br> a. dotted<br> b. y=-x+4<br> c. y=x-4<br> d. y=x+1<br> e. solid<br> f. yes<br> g. no
Ksenya-84 [330]

Answer:

Those answers are correct

5 0
3 years ago
Sara scored 8 goals this season. This is two less than a third of the goals she scored last season.
Charra [1.4K]

Answer:

30 goals last season

Step-by-step explanation:

Goals this season = 8

Goals this season = 1/3 of goals last season - 2

Let Goals scored last season = x

Therefore,

8 = 1/3x - 2

8 = x/3 - 2

8 + 2 = x / 3

10 = x / 3

x = 10 * 3

x = 30

Sara scored 30 goals last season

3 0
3 years ago
Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the dif
rodikova [14]

Answer:

60men 40 women.... but I ain't sure

4 0
4 years ago
Find the area of the shaded region .
Greeley [361]

Calculate area of the white region inside circle.

Area of the two white triangles in top left and bottom right:

2 \cdot \frac{1}{2}(6)(6) = 36 ft^2

Area of the two white quarter circles in the bottom left and top right:

2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2

Total area of unshaded white region inside circle:

(36 + 18\pi)ft^2

Area of entire circle including the white and shaded regions

\pi(6)^2 = 36\pi ft^2

Area of shaded region is area of entire circle - area of unshaded white region

36\pi - (36 + 18\pi) = (18\pi - 36) ft^2

7 0
3 years ago
The amount of time required for an oil and filter change on an automobile is normally distributed with a mean of 45 minutes and
Firdavs [7]

Answer:

1a

  P(39 <  X < 48  ) = 0.8767

1b

    95% of all sample means will fall between 40.1  <  \mu < 49.9

1c

    \= x = 41. 795

2

   n =  25

Step-by-step explanation:

From the question we are told that

   The mean is n   =  45

   The population standard deviation is  \sigma =  10

   The sample size is n  =  16

Generally the standard error of the mean is mathematically represented as

       \sigma_{x} =  \frac{ \sigma}{\sqrt{n} }

=>    \sigma_{x} =  \frac{ 10 }{\sqrt{16 } }

=>    \sigma_{x} = 2.5

Generally the probability that the sample mean will be between 39 and 48 minutes is

    P(39 <  X < 48  ) =  P( \frac{ 39 - 45}{ 2.5} <  \frac{X - \mu }{\sigma } <  \frac{ 48 - 45}{ 2.5} )

=> P(39 <  X < 48  ) =  P(-2.4 < Z< 1.2 )

=> P(39 <  X < 48  ) =  P( Z< 1.2 ) - P(Z <  -2.4)

From the z table  the area under the normal curve to the left corresponding to  1.2  and  -2.4  is

=> P( Z< 1.2 ) = 0.88493

and  

    P( Z< - 2.4 ) = 0.0081975

So

   P(39 <  X < 48  ) = 0.88493 -0.0081975

=> P(39 <  X < 48  ) = 0.8767

From the question we are told the confidence level is  95% , hence the level of significance is    

      \alpha = (100 - 95 ) \%

=>   \alpha = 0.05

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

=>   E = 1.96 * 2.5  

=>   E =4.9  

Generally the  95% of all sample means will fall between

      \mu  -E <  and   \mu   +E

=>   45  -4.9\   and \  45  + 4.9

Generally the value which  90% of sample means is  greater than is mathematically represented

      P( \= X >  \= x  ) = 0.90

=>   P( \= X >  \= x  ) =  P( \frac{\= X  - \mu }{ \sigma_x} >  \frac{\= x  -45 }{ 2.5}  ) = 0.90

=>  P( \= X >  \= x  ) =  P( Z >  z  ) = 0.90

Generally from the z-table  the critical  value  of  0.90  is  

      z = -1.282

      \frac{\= x  -45 }{ 2.5}  = -1.282

=>   \= x = 41. 795

Considering question 2

 Generally we are told that the standard deviation of the mean to be one fifth of the population standard deviation, this is mathematically represented as

         s = \frac{1}{5} \sigma

  Generally the standard deviation of the sample mean is mathematically  represented as

          s = \frac{\sigma }{ \sqrt{n} }

=>       \frac{1}{5} \sigma = \frac{\sigma }{ \sqrt{n} }

=>       n =  5^2

=>       n =  25

5 0
3 years ago
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