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Makovka662 [10]
3 years ago
12

I need help for this

Mathematics
1 answer:
Alenkasestr [34]3 years ago
5 0
Answers is
A'= -3,3
B'=4,-1
C'=-2,0
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This year martin earned $ 1,615mowing lawns, shoveling driveways, and doing yard work. This is 19 times as much as he earned las
saul85 [17]

Answer:

$85

Step-by-step explanation:

To find the answer, we need to divide 1,615 by 19, since it says he earned 19 times the amount last year.

1,615/19=85

He only earned 85 dollars last year.

Hope this helps!

7 0
4 years ago
7m plus 8 equals 71 <br> How do u solve
Elden [556K]

Answer: m=9

Step-by-step explanation:

Step 1: Subtract 8 from both sides: 7m+8-8=71-8

7m=63

Step 2: Divide both sides by 7: 7m/7=63/7

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3 years ago
A merchant buys a television for $125 and sells it for a retail price of $200. What is the markup
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The markup is the percent of the original price that it is increased by. To determine the percentage marked up, you will subtract the new price and the original price, and then divide that by the original price.

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4 years ago
Joey is trying to determine the average weight of a frog found at his high school's pond. The Algebra II class randomly selects
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0.06

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3 years ago
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
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