Answer: y - 3 = 0.041(x - 27)
Step-by-step explanation:
y = log3 x; (27, 3)
Step 1
Find the point of tangency.
It's given as (27,3)
Step 2
Find the first derivative, and evaluate it at x=27
Differentiating log3 x.
Note we can't directly differentiate log3 x, we need to convert it to natural log = ln.
Using change of base.
Log3 x = lnx/ln3
So,
d(lnx/ln3)/dx = 1/ln3 × 1/x
f'(x) = 1/xln3
f'(27) = 1/27ln3 = 0.041
The slope of the tangent line at this point is m= 0.041
Step 3
Find the equation of the tangent line at (27,3) with a slope of m=0.041
y−y1 = m(x - x1)
y - 3 = 0.041(x - 27)
Answer:
6x-12
Step-by-step explanation:
I think this is the answer I am so sorry if Im wrong but 3*2x = 6x and then -4*3 = -12
Your answer would be -1+11p
Hope this helps!
//Add 6 to both sides:
//Multiply by -1 on both sides:
Multiply by 3 on both sides:
Divide by 4 on both sides:
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Answer: x = 15 (Answer C)-----------------------------------------
(X + 5)(x+3) in factored form
So x + 5 = 0 and x + 3 = 0, therefore,
X = -5 and x = -3