21 divided by 7 is 3. So he would have ate 3 scopes a day.
Yes quadrilaterals can be squares
2(3x+5)=9x+9-3x+1
(2)(3x)+(2)(5)=9x+9-3x+1
6x+10=9x+9-3x+1
6x+10=(9x-3x)+(9+1)
6x+10=6x+10
6x-6x+10=6x-6x+10
10=10
10-10=10-10
0=0
All real numbers are solutions.
A) y=2x2-28x+52 ion think it’s any other but I might be wrong
Answer:
Step-by-step explanation:
A. f(x) = (2x-3)(x-1)
B. since the coefficient of x^2 is positive, the parabola opens upward.
C. plot the vetex, which is between the roots, at x = 5/4, plot the zeroes
plot the points at x=1,2, draw a curve through them.
You can use any of several handy online graphing tools to verify your work.
