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3 years ago

If you add 5 to me and then divide by 9 you get 3 what number am I

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

7 0

Form an equation using the information provided
x = number
(x + 5)/9 = 3
multiply by 9
x + 5 = 27
then solve
x = 22

Katyanochek1 [597]3 years ago

3 0

You are simply reversing the equation

(X+5)/9=3

First times 3 by 9 giving you 27

X+5=27

Now subtract 5 to get your answer

27-5=22

and 22 is your answer!!!!

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Area = the top semicircle + the rectangle AEBD

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3 years ago

Use the distributive property to expand the following expression:

KIM [24]

Answer:

This is guess of what the question is asking:

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3 years ago

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3 years ago

Consider an angle with a measure of θ=225∘.

wel

Answer:

cos 225° = $-\frac{\sqrt{2} }{2}$

sin 225° = $-\frac{\sqrt{2} }{2}$

tan 225° = 1

Step-by-step explanation:

I cannot sketch a diagram, but a 225° angle is a 3rd quadrant angle and the reference angle is 45° (225 - 180 = 45)

cos and sin are negative in the 3rd quadrant and the tan is positive

cos 225° = - cos 45° = $-\frac{\sqrt{2} }{2}$

sin 225° = -sin 45° = $-\frac{\sqrt{2} }{2}$

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8 0

2 years ago

Determine whether the integral is convergent or divergent. [infinity] 7 e−1/x x2 dx convergent divergent Changed: Your submitted

inessss [21]

I suppose the integral could be

$\displaystyle\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx$

In that case, since $-\frac1x\to0$ as $x\to\infty$ , we know $e^{-1/x}\to1$ . We also have $\left(e^{-1/x}\right)'=\frac{e^{-1/x}}{x^2}>0$ , so the integral is approach +1 from below. This tells us that, by comparison,

$\displaystyle\frac{e^{-1/x}}{x^2}\le\frac1{x^2}\implies\int_7^\infty\frac{e^{-1/x}}{x^2}\,\mathrm dx\le\int_7^\infty\frac{\mathrm dx}{x^2}$

and the latter integral is convergent, so this integral must converge.

To find its value, let $u=-\frac1x$ , so that $\mathrm du=\frac{\mathrm dx}{x^2}$ . Then the integral is equal to

$\displaystyle\int_{-1/7}^0e^u\,\mathrm du=e^0-e^{-1/7}=1-\frac1{\sqrt[7]{e}}$

4 0

3 years ago