The lowest number was 11

Slav-nsk [51]

$(\frac{x + 1}{x} ) ^{2} \\ = \frac{ {(x + 1)}^{2} }{ {x}^{2} } \\ = \frac{ (x + 1)(x + 1) }{ {x}^{2} } \\ = \frac{ {x}^{2} + 2x + 1}{ {x}^{2} }$

Hope you could get an idea from here.

Doubt clarification- use comment section.

4 0

2 years ago

Please asap I need this for a test

ki77a [65]

Answer:

3

Step-by-step explanation:

(f O g) this basically means that the input x first goes trough the function g and then f. Like f(g(x)).

So when x went trough g, you got the output g(x) and then this went trough f and you got f(g(x)) = -8 = 'f(x)'.

With this in mind you can retrace your steps by first looking at what input can get -8 as an output, for f this is -4. this means g(x) = -4

Then you look at what input (this is the x you're looking for) gets you the ouput -4. Looking at the second image you'll picture see that it's the input 3.

4 0

2 years ago

D. Evaluate each of the following. (5 points)

Harrizon [31]

Problem 1

f(x) = x + 1/x

f(1) = 1 + 1/1

f(1) = 1 + 1

f(1) = 2

Answer: 2

============================================

Problem 2

(f o f)(1) = f( f(1) )

(f o f)(1) = f( 2 )

(f o f)(1) = 2 + 1/2

(f o f)(1) = 4/2 + 1/2

(f o f)(1) = 5/2

Answer: 5/2

============================================

Problem 3

(f o f o f)(1) = f( f(f(1)) )

(f o f o f)(1) = f( (f o f)(1) )

(f o f o f)(1) = f( 5/2 )

(f o f o f)(1) = 5/2 + 1/(5/2)

(f o f o f)(1) = 5/2 + 2/5

(f o f o f)(1) = 25/10 + 4/10

(f o f o f)(1) = 29/10

Answer: 29/10

============================================

Problem 4

(f o f o f o f)(1) = f( f(f(f(1)) )

(f o f o f o f)(1) = f( (f o f o f)(1) )

(f o f o f o f)(1) = f( 29/10 )

(f o f o f o f)(1) = 29/10 + 1/(29/10)

(f o f o f o f)(1) = 29/10 + 10/29

(f o f o f o f)(1) = 841/290 + 100/290

(f o f o f o f)(1) = 941/290

Answer: 941/290

============================================

Problem 5

(f o f o f o f o f)(1) = f( f(f(f(f(1)))) )

(f o f o f o f o f)(1) = f( (f o f o f o f)(1) )

(f o f o f o f o f)(1) = f( 941/290 )

(f o f o f o f o f)(1) = 941/290 + 1/(941/290)

(f o f o f o f o f)(1) = 941/290 + 290/941

(f o f o f o f o f)(1) = 885481/272890 + 84100/272890

(f o f o f o f o f)(1) = 969581/272890

Answer: 969581/272890

4 0

3 years ago

Read 2 more answers

Generate a sampling distribution of sample means using a sample of size from the YearlySalary values in the dataset NFLContracts

rjkz [21]

Answer:

Hello your question is not well written attached below is the complete question

answer :

a) smallest value = $0.405 million

largest value = $22 million

b) smallest value = $0.505 million

largest value = $9.332 million

Step-by-step explanation:

A) what are the smallest and largest yearly salary values in the population

smallest value = $0.405 million

largest value = $22 million

b) What are the smallest and largest sample mean in the sampling distribution

Smallest value = $0.505 million

Largest value = $9.332 million

note : values where gotten using statkey on the dataset NFLcontracts2015 as stated in the attached document ( question )

8 0

3 years ago

A business owner collected data on the people working for her company. She determined the average number of minutes each employe

Naddika [18.5K]

Answer:

The comparison using median and IQR is best because one of the graphs is not symmetrical.

Step-by-step explanation:

The following information is missing

A box plot titled Number of Minutes Women Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 54, and the box ranges from 34 to 50. A line divides the box at 48.

A box plot titled Number of Minutes Men Spend on Breaks. The number line goes from 30 to 70. The whiskers range from 30 to 68, and the box ranges from 36 to 60. A line divides the box at 48.

The business owner uses the median and IQR to determine the center and variability of the data sets. Which best describes the comparison?

The comparison would be more accurate using the mean and MAD because one of the graphs is symmetric.

The comparison would be more accurate using the mean and MAD because the median of both data sets is the same.

The comparison using median and IQR is best because one of the graphs is not symmetrical.

The comparison using median and IQR is best because the median is greater than the IQR for both data sets.

Mean and MAD are useful for comparison when both data sets are symmetrical.

In the women box plot the Q1 is at 34, the median is at 48, and the Q3 is at 50, so it is not symmetrical (the difference between the median and the Q1, and the Q3 and the median is not the same)

8 0

3 years ago