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Ilia_Sergeevich [38]

3 years ago

14

isabella is covering a square tabletop with square mossaic tiles.the tabletop is 2ft. long and 2ft.wide.each tile is 1/4 in.long

and 1/4in.wide.what is the minimum number of tiles needed to cover the tabletop?

1 answer:

Hunter-Best [27]3 years ago

5 0

Convert the feet to inches first. 2 ft = 24 inches. We must divide this total length by the length of each tile to determine how many tiles will fit across the tabletop:

24 ÷ (1/4) = (24/1) ÷ (1/4) = (24/1) × (4/1) = 96/1 = 96

96 tiles will fit across the tabletop.
Since the tabletop is as long as it is wide, that means we will have 96 rows of 96 tiles:
96(96) = 9,216 tiles to cover the tabletop.

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