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Mrac [35]
3 years ago
7

The length of a rectangle is 3 inches longer then twice its width, where w is the width of the rectangle the area of the rectang

le is 90 square inches. Write an equation that represents the area and find the width and length of the rectangle.
Mathematics
1 answer:
vaieri [72.5K]3 years ago
6 0
A = w(2w + 3)
90 = 2w^2 + 3w
2w^2 +3w - 90 = 0
(w-6)(2w+15) = 0        (TRINOMIAL FACTORING)
w = 6 inch                   ( it can't be -15/2 because lengths can't be negative)
l = 2w + 3
  = 15 inch
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Day \ \ \ \ \ \ \ \ \ \ Period \ \ \ \ \ \ \ \ \ \ Demand \ \ \ \ \ \ \ \ \ \ 5-period moving average

1 \ \ \ \ \ \ \ \ \ \ \  Morning \ \ \ \ \ \ \ \ \ \ \ 37 \\\\

            Afternoon \ \ \ \ \ \ \ \ \ \ \ 25  \\\\ Evening \ \ \ \ \ \ \ \ \ \ \  9

2 \ \ \ \ \ \ \ \ \ \ \  Morning \ \ \ \ \ \ \ \ \ \ \48 \\\\

           Afternoon\ \ \ \ \ \ \ \ \ \ \ 28 \\\\

            Evening \ \ \ \ \ \ \ \ \ \ \ 14 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  29.4 \\\\

3 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ 53 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  24.8\\\\

              Afternoon \ \ \ \ \ \ \ \ \ \ \ 33 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  30.4\\\\Evening \ \ \ \ \ \ \ \ \ \ \ 17 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35.2\\\\

4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ 29\\\\

                 Afternoon\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 29.25\\\\Evening \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34.33333\\\\

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