Answer:
Explanation:
A mixture of pulverized fuel ash and Portland cement to be used for grouting should have a compressive strength of more than
1300 KN/m2. The mixture will not be used unless experimental evidence indicates conclusively that the strength specification has been met. Suppose compressive strength for specimens of this mixture is normally distributed with ? = 68. Let ? denote the true average compressive strength.
(b) Let
X
denote the sample average compressive strength for n = 11 randomly selected specimens. Consider the test procedure with test statistic X and rejection region x ? 1331.26. What is the probability distribution of the test statistic when H0 is true? (Round your standard deviation to three decimal places.)
(c) What is the probability distribution of the test statistic when
? = 1350? (Round your standard deviation to three decimal places.)
Using the test procedure of part (b), what is the probability that the mixture will be judged unsatisfactory when in fact
? = 1350 (a type II error)? (Round your answer to four decimal places.)
(d) How would you change the test procedure of part (b) to obtain a test with significance level 0.05? (Round your answer to two decimal places.) Replace 1331.26 KN/m2 wit
What impact would this change have on the error probability of part (c)? (Round your answer to four decimal places.)
The probability that the mixture will be judged unsatisfactory when in fact ? = 1350 will change to .
(e) Consider the standardized test statistic
Z = (X ? 1300)/(?/n).
What are the values of Z corresponding to the rejection region of part (b)? (Round your answer to two decimal places.)
Answer:
weight will be become
So option (C) will be correct answer
Explanation:
We have given mass of the earth is and radius of earth is
Acceleration due to gravity on earth is given by
Weight is equal to , as mass is always conserved so weight is dependent on acceleration due to gravity
Now radius is
So acceleration due to gravity is
As weight is directly related to acceleration due to gravity
So weight will be become
So option (C) will be correct answer
The lane that can be used for both entering and exiting a highway is called; A weave lane
<h3>How to enter a highway?</h3>
When it comes to road highways, there are different terminologies that apply such as Acceleration lane, Deceleration Lane, Interchange, Weave lane, Urban roadway e.t.c
However, when it comes to the one that can be used for both entering and exiting a highway, the correct answer will be Weave Lane because it has both an entrance and an exit for an expressway. Traffic may come onto and leave the expressway at the same location.
Read more about road highway at; brainly.com/question/12961781
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Answer:
A) 2P/(¶r^2)
B) p/(¶r^2)
Explanation:
Force = P
Radius = r
Area on which force acts = ¶r^2
If both forces are applied, total stress will be
S = 2P/(¶r^2)
When only one of the force is applied
S = p/(¶r^2)
Answer: Either your computer is malfunctioning or it is glitched and still thinks you only have 2. Also good job
Explanation: Leave a brainliest it helps