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3 years ago

8

A team of engineers is tasked with designing a hydraulic engine for a motorboat that is as efficient as possible. Identify three

of the
seven design phases, and explain why they are individually important in the design process.
Help ASAP!

1 answer:

Rina8888 [55]3 years ago

7 0

Answer:

Driving surface area as subject to differential pressures
How to achieve continuous rotation
Mechanical connections

Explanation:

The general stages of thinking when designing a system are;

First understanding the problem that requires you to design a solution
Defining the problem that needs to be solved. In this case is to design an efficient hydraulic engine for a motorboat
Research to find any available solutions for similar problems
Idea of the solution
A prototype to try solve the challenge
Selecting and adjusting the prototype as you implement the solution.

For a hydraulic engine design, the following designing parts are vital;

Driving surface area as subject to differential pressures
How to achieve continuous rotation
Mechanical connection

Pressures are important due to motor displacements. Fuel burns in the cylinder to cause power through fuel gases burning and expansion which is the four-stroke cycle. Continuous rotation will come in the design considerations through reciprocating motions of pistons into rotary motions. Mechanical connections are vital especially in crank shaft turns, gear box that turns horizontal motions to spinning motions and finally the propeller that drives the boat on the water.

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5 0

3 years ago

A and B connect the gear box to the wheel assemblies of a tractor, and shaft C connects it to the engine. Shafts A and Blie in t

azamat

Answer:

The couples are not all on one axis or plane for that matter but if the A and B connector had to be specified it would go by the yz axis diagonal to the x axis with a magnitude of about 15. The direction of the axis would be pointed up to the second quadrant. Hope this was helpful

Explanation:

8 0

4 years ago

The larger the Bi number, the more accurate the lumped system analysis. a)-True b)- False

mrs_skeptik [129]

Answer:

b). False

Explanation:

Lumped body analysis :

Lumped body analysis states that some bodies during heat transfer process remains uniform at all times. The temperature of these bodies is a function of temperature only. Therefor the heat transfer analysis based on such idea is called lumped body analysis.

Biot number is a dimensionless number which governs the heat transfer rate for a lumped body. Biot number is defined as the ratio of the convection transfer at the surface of the body to the conduction inside the body. the temperature difference will be uniform only when the Biot number is nearly equal to zero.

The lumped body analysis assumes that there exists a uniform temperature distribution within the body. This means that the conduction heat resistance should be zero. Thus the lumped body analysis is exact when biot number is zero.

In general it is assume that for a lumped body analysis, Biot number $\leq$ 0.1

Therefore, the smaller the Biot number, the more exact is the lumped system analysis.

7 0

3 years ago

Consider a voltage v = Vdc + vac where Vdc = a constant and the average value of vac = 0. Apply the integral definition of RMS t

Anna11 [10]

Answer:

Proof is as follows

Proof:

Given that , $V = V_{ac} + V_{dc}$

<u>for any function f with period T, RMS is given by</u>

<u /> $RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[f(t)]^{2} } \, dt }$ <u />

In our case, function is $V = V_{ac} + V_{dc}$

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac} + V_{dc}]^{2} } \, dt }$

Now open the square term as follows

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {[V_{ac}^{2} + V_{dc}^{2} + 2V_{dc}V_{ac}] } \, dt }$

Rearranging terms

$RMS = \sqrt{\frac{1}{T}\int\limits^T_0 {V_{dc}^{2} } \, dt + \frac{1}{T}\int\limits^T_0 {V_{ac}^{2} } \, dt + \frac{1}{T}\int\limits^T_0 {2V_{dc}V_{ac} } \, dt }$

You can see that

second term is square of RMS value of Vac

Third terms is average of VdcVac and given is that average of $V_{ac}V_{dc} = 0$

so

$RMS = \sqrt{\frac{1}{T}TV_{dc}^{2} + [RMS~~ of~~ V_{ac}]^2 }$

$RMS = \sqrt{V_{dc}^{2} + [RMS~~ of~~ V_{ac}]^2 }$

So it has been proved that given expression for root mean square (RMS) is valid

7 0

3 years ago

What is the standard deviation of the following data set:

EastWind [94]

Answer:

See Explanation

Explanation:

The question is incomplete as the data set are missing. However, I'll use the following data to answer your question:

<em>5,12,3,18,6,8,2,10 </em>

Start by calculating the mean:

$Mean = \frac{\sum x}{n}$

$Mean= \frac{5+12+3+18+6+8+2+10}{8}$

$Mean= \frac{64}{8}$

$Mean = 8$

Standard deviation is calculated using:

$SD = \sqrt{\frac{(x_i - Mean)^2}{n}}$

This gives:

$SD = \sqrt{\frac{(5 - 8)^2+(12 - 8)^2+(3 - 8)^2+(18 - 8)^2+(6 - 8)^2+(8 - 8)^2+(2 - 8)^2+(10 - 8)^2}{8}}$

$SD = \sqrt{\frac{(-3)^2+(4)^2+(- 5)^2+(10)^2+(-2)^2+(0)^2+( - 6)^2+(2)^2}{8}}$

$SD = \sqrt{\frac{9+16+25+100+4+0+36+4}{8}}$

$SD = \sqrt{\frac{194}{8}}$

$SD = \sqrt{24.25}$

$SD = 4.92$

<em>Apply the above steps in the original question, then you will get your correct answer.</em>

3 0

3 years ago