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Alex_Xolod [135]
4 years ago
13

????????????????????

Mathematics
1 answer:
Arlecino [84]4 years ago
3 0

Answer:

its b

Step-by-step explanation:

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Given: triangle ABC and triangle EDC, C is the midpoint of BD and AE. <br>Prove: AB || DE
VladimirAG [237]

Step-by-step explanation:

1. ΔABC=ΔCDE: a) according to the condition BC=CD and AC=CE; b) m∠(BCA)=m∠(DCE).

2. if ΔABC=ΔCDE, then m∠(BAC)=m∠(DEC) and m∠(ABC)=m∠(CDE).

3. if m∠(BAC)=m∠(DEC), then AB || DE (or if m∠(ABC)=m∠(CDE), then AB || DE).

5 0
3 years ago
the length of a rectangle in (3+√7) and it's with is (1+2√7). what is the area of the rectangle? what is the perimeter of the re
Eddi Din [679]

Answer:

Area: (3+√7) x (1+2√7) = 17+7√7 = 35.52

Perimeter: 2(3+√7) + 2(1+2√7) = 8+6√7 = 23.87

7 0
3 years ago
Pls help! evaluate the sine of the real number, pls give exact answers
solong [7]

Answer:

 -\frac{\sqrt2}{2} \\  or exact is −0.70710678...

Step-by-step explanation:

Getting the point!

  1. If we look at the unit circle and we find -\frac{3\pi }{4} we see it is in the 3rd quadrant.
  2. We know that all points in the 3rd quadrant have both negative x and negative y values.
  3. We know that all radians with the base of 4 on the unit circle have the points of (\frac{\sqrt{2}}{2} ,\frac{\sqrt{2}}{2})
  4. Because we are in the 3rd quadrant and both x and y are negative we know the point of -\frac{3\pi }{4}  is (-\frac{\sqrt{2}}{2}, -\frac{\sqrt{2}}{2})

Finding the sin!

  1. Because we know that sin is asking us for the y value
  2. We can just look at the point and find the y value!
  3. the y value is -\frac{\sqrt2}{2} \\
  4. Because this fraction does not need to be rationalized we are good!
  5. Use a calculator to find the exact value and you get -0.70710678...
  6. The final answer is  -\frac{\sqrt2}{2} \\ or exact is −0.70710678...

Hope this helps!! Please mark Brainliest!

4 0
2 years ago
Tan x/sec^2 x + tan x/csc^2 x​
Arada [10]

I guess you're supposed to simplify?

\dfrac{\tan x}{\sec^2x}+\dfrac{\tan x}{\csc^2x}

=\tan x\left(\dfrac1{\sec^2x}+\dfrac1{\csc^2x}\right)

=\tan x(\cos^2x+\sin^2x)

=\tan x

5 0
4 years ago
4(4a 7) 3(2a 5) if the a=5
Anarel [89]
4(4a 7 ) 3(2a 5) = 4 ( 4 x 5 x 7 ) x 3 ( 2 x 5 x 5 ) = 560 x 150 = 84000
3 0
3 years ago
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